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Questions (4)
how do i calculate the point on the curve when the ordinate changes 8 times faster than abscissa in the equation 6y=x^3+2
3 answers
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15 ml of 0.5 M of HCl is added to a 100 ml sample of 0.2 M HNO2 (Ka for HNO2= 4.0 x 10^(-4)). What is the equilibrium
2 answers
629 views
I thought I was answering:
http://www.jiskha.com/display.cgi?id=1234647827
1 answer
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For a given mass of solute per liter of solution, the larger to formula mass, the lower the osmotic pressure. Osmotic pressure
2 answers
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Answers (631)
thank you
answer is 7
.84
absolutely the answer is zero. note the question it says net force .
precisely 299.99999999 by the formula I=P/r(pi)r^2 .
IT is Absolutely right . The answer is 8
The answer is "yes" but I am not sure what formula you are referring to. Are you expected to use the absorbance v. time graph to get the half-life? If so, •Select a point on the graph with a high value for absorbance, A. Read the time in minutes, T1.
[H+] = 10^-2 = 0.01M 10 ml = 0.010L (0.01mol/L)(0.010L) = 0.0001 mole of H+ or HCl moles of Zn = (0.0001 mol HCl)(1mol Zn/2mol.HCl)= 0.00005 moles Zn Convert moles of Zn to grams
3.15 mol / 0.250 kg = 12.6 mol/kg or 12.6 molal The boiling point of a solution is Tb = Tb(H2O) + deltaT = 100º + deltaT deltaT = Kb*m = (0.512deg.kg/mol)(12.6mol/kg) NOTE: C2H6O2 is not ethylene. It may be CH3-O-O-CH3 whose solubility could not be
Chemical means of fighting oil spills are generally detergents which break up big blobs of oil into small liquid drops that are dispersed and eventually broken down by bacteria. This involves a whole sequence of physical and chemical changes. You can't
1. sodium metal reacts (burns) in chlorine gas forming sodium chloride, NaCl. 2. The ability of water to dissolve ionic solids (most salts) and polar molecular compounds (sugars, alcohols, ammonia, etc) is because of its polarity and its ability to form
If anyone can prepare a 1 M solution of Mg(OH)2, I would like to see it. The solubility of of magnesium hydroxide in water is 12 mg/L. The Ksp is 4.5x10^-11.
KClO3 decomposes to KCl and O2 which it escapes. A sample of KClO3 that has had some decomposition will contain some KCl. A sample of this mixture could be dissolved in water and tested with AgNO3. Pure KClO3 would not produce a precipitate since AgClO3 is
I assume the desired pH is 8.65 although you did not label it, as DrBob pointed out. Ka = [H+][NO2-] / [HNO2] [H+] = antilog(-8.65)=2.24x10^-9 (a basic solution) [OH-] = Kw / [H+] [OH-] = (1x10^-14)/(2.24x10^-9) = 4.47x10^(-6) Ka = [H+][NO2-] / [HNO2] =
We need the chemical equation for the reaction between CH4 and O2. I assume it was: 2CH4 + 3O2 -->2CO + 4H2O To answer your question, 1. Divide 45.6g by the molar mass of CH4 to get the number of moles of CH4. 2. Divide 73.2g O2 by the molar mass of O2 to
The mass of 1 liter of water is very close to 1 kg q = (specific heat)*(mass)*deltaT specific heat of water = 4.18kJ/kg.C q = (4.18kJ/kg.C)(1.00kg)(85ºC-18ºC)
Start with: CH3CH2CH2-C-OCH(CH3)2 To the middle -C-, attach an -OH (up) and an -H (down). See also: http://en.wikipedia.org/wiki/Hemiacetal
Para (p-), meta (m-), and ortho (o-) are only used for derivatives of benzene. Your acid was probably 4-methylcyclohexanoic acid.
CH3CH2CH2CH2OH + NaBr --> CH3CH2CH2CH2Br + NaOH. NaOH would react with H2SO4 to form Na2SO4 which may precipitate in a mixture of organic solvents.
The deltaH for the decomposition of 1 mole of Al2O3 is half of 351.4 kJ since the chemical equation shows 2 moles of Al2O3. Convert 12.50g Al2O3 to moles by dividing it by the molar mass of Al2O3. Multiply your answer by 351.4kJ to get the enthalpy of
Salicylic acid which was probably used to make aspirin is a phenol. The negative phenol test indicates that all of the salicylic acid reacted. However, the aspirin produced was not pure. Impurities lower the melting point and make the melting point range
2-methyl-2-pentanol
1. Errors related to the measurement of volume of acetic acid (what volumetric glassware was used and how it was used). 2. Errors related to using and reading the buret with the NaOH solution. 3. Errors related to reaching the endpoint. Color, etc. 4.
The unpaired electron in the ethyl radical can be more easily delocalized by two carbon atoms, and through the increase in the number of resonance forms in a two-carbon chain.
nf would be the square root of some positive value, but your (A) and (B) look the same. Did you copy these alternate answers correctly?
1/lambda = R/ni^2–R/nf^2 y = mx + b (standard form) of a linear equation) x = (y-b)/m Let, y = 1/lambda m = -R x = 1/nf^2 b = R/ni^2 1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R) Solve for nf
Surface tension is the result of intermolecular forces. Viscosity is also the result of intermolecular forces plus additional factors such as entanglement of long molecules. What intermolecular forces are involved from C6H14 to C9H20? How would the
•Find the difference in electronegativity between H and F. •Find the difference in elctronegativity between H and I. •Compare the two differerences. The larger difference indicates the larger polarity.
The equilibrium constant expression is: K(eq)=[N2][O2] / [NO]^2 = 8.36*10^3 Substitute the concentrations given and solve for [NO]
[Answered elsewhere]
In a Bronsted-Lowry acid-base reaction with a high Keq value, Acid + Base = Weaker acid + Weaker Base Acid1 + Base1 = Base2 + Acisd2 Acid1 is stronger than Acid2, and, Base1 is stronger than Base2 In your question, the equilibrium constant is small. The
K(eq) = [CH3OH] / [CO][H2]^2 let [CH3OH] = [x] Substituting, 10.2 = [x] / [0.02][0.02]^2 Solve for [x]
Statements A, B, and C are correct.
A gas mixture in a container may start heterogeneous but the constant, random motion of the molecules in it will make it homogeneous in a very short time.
Is the question about the mole ratio in the product or the mixture?? If the product is CuS, the mole ratio in the product is 1molCu/1molS=1 molCu/molS The mole ratio of the masses of the elements in any compound is definite, not dependent on the reactants
Convert deg. C to deg. K, then substitute into the Combined Gas Law: P1V1/T1 = P2V2/T2 Solve for V2. Your answer is not correct.
Convert degrees C to degrees K. K = C + 273 Convert torrs to atm. atm = torrs / 760 Substitute in PV = nRT and solve for V
The oxidizing agent, Ag+, gained an electron and is reduced to Ag(s). The reducing agent loses an electron and is oxidized from Fe^2+ to Fe^3+: Ag^+(aq) + Fe^2+(aq) --> Ag(s) + Fe^3+(aq)
Cm has 96 electrons. The previous noble gas is radon, Rn, with 86 electrons. It is a 7th row element and a member of the actinide series which starts with Ac, 3rd element on the 7th row and 7th element on the actinium series. The electron configuration is:
NaOH + HClO4 --> H2O + NaClO4
Valence electrons are easier to remove (ionize) than electrons in the shell under the valence shell. A complete shell, closer to the nucleus is more difficult to disturb. After the valence electrons are removed, removal of an electron from the shell below
The unbalanced chemical equation is: H2SO4 + Pb(OH)4 --> Pb(SO4)2 + H2O Balancing the SO4 groups (2 of them): 2H2SO4 + Pb(OH)4 --> Pb(SO4)2 + H2O Balancing the H's (8 of them): 2H2SO4 + Pb(OH)4 --> Pb(SO4)2 + 4H2O
The reaction is: Al2S3 + 6AgNO3(aq) --> 3Ag2S(s) + 2Al(NO3)3(aq) Find the formula mass (molar mass) of Al2S3. Divide 300.23 g by the formula mass to get moles of Al2S3. Moles of Ag2S = (__moles Al2S3)(3) Moles of Al(NO3)3 = (__moles Al2S3)(2)
Most fuels are molecular (covalent) compounds as bobpursley pointed out. Ionic compounds do not burn. Note: Some ionic materials may decompose violently or support combustion (NaNO3, KClO4, etc.) Cesium sulfide is a stable compound that does not burn.
Yes, since we have only two groups of valence electrons around the central atom, C: H : C : : : N :
The reaction written correctly is: 2NiO (s)--> 2Ni(s) + O2 (g) 1. Divide 25.67g NiO by the formula its mass to get the number of moles of NiO. 2. Since 2 moles NiO produce 1 mole O2, moles of O2 = ( ___mol NiO)(1/2) 3. Look up the vapor pressure of water,
The phosphate formula depends on the oxidation state of the vanadium ion. For example, vanadium(III) phosphate would be VPO4 and vanadium(II) phosphate V3(PO4)2.
Every chemical reaction involves definite mole ratios. That is the meaning of stoichiometry. A baking cake involves several complex chemical changes with precise mole ratios of reactants and products to each other. That is difficult to show and has little
Check the previous post at: http://www.jiskha.com/display.cgi?id=1260062043
(a) A high activation energy may slow down a spontaneous reaction to the point that it does not occur at a visible rate. (b) A reaction is spontaneous because it leads to lower potential energy (deltaH is negative) and/or it increases entropy (deltaS is
