Question

The first step of the synthesis is described by the reaction below. When 1.750 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4 , the theoretical yield of FeC2O42H2O is
_______grams.

Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)


Please help me. I tried everything. =(

Answer 1

*Convert 1.750g of Fe(NH4)2(SO4)2•6H2O to moles by dividing by the molar mass of this compound.
*Find the moles of H2C2O4 using:
moles = (liters)(mol/L)
Te moles ratio of the two reagents id 1 to 1. That means that the <b>smaller</b> number of moles belongs to the <b>limiting reagent</b>.
To get the theoretical yield of FeC2O42H2O, multiply the moles of the limiting reagent by the molar mass of this product.