Question

Identify the limiting reagent and the volume of product formed with 11L CS2 reacts with 18L O2 to prduce CO2 gas and SO2 gas.
CS2+3O2-->CO2+2SO2

Answer 1

When you have gases at the same temperature and pressure, the volume ratio is equal to the mole ratio. The ratio of the coefficients in the chemical equation can be used as mole ratios OR volume ratios:
(11L CS2)(3 L O2 / 1 L CS2) = 33 L O2 *needed*
Since only 18 L O2 are *available*, which is the limiting reagent?

Answer 2

i don't get it

Answer 3

11 L CS2 needs 33 L O2 and you have only 18 L O2. So which is the limiting reagent? oxygen or CS2?