What is the limiting reagent when 10.8 g water reacts with 4.7 g Na to produce NaOH and H2?

Answer 1

The first step to this problem is to write out reaction and balance it.

H2O + Na ---> NaOH + H2

The balance reaction looks like the following

2H2O +2 Na--->2NaOH + H2

This lets you know that the mole ratio between H2O and Na for this reaction to proceed must must be equal.

Convert grams of each to moles

10.8 g of H2O/18 g of H20/mole = number of moles H2O

4.7 g of Na/23.0 g of Na/mole = number of moles of Na

The compound with the least number of moles is the limiting reagent.

Answer 2

180

Answer 3

23