Devron

what is this compound, it has a mf of c6h12o i. imgur. com/gCgw0Hi. png What may be the structure from the IR and H NMR data? This question is bugging me.

12 years ago

I believe that you are correct because you have more experience in G-chem then I have. But how does doubling the reaction rate double the k value? Isn't k just a constant for a particular reaction?

12 years ago

I agree with 0.0918 mols C and 0.137 mols H but not the formula. 0.137/0.0918 = about 1.5; is that C2H3? And the balanced equation is 4C2H3 + 11O2 ==> 8CO2 + 6H2O I've not heard of C2H3? Okay, I have never heard ofC2H3 as well, so I had to take the number...

12 years ago

When you get a chance: If the pure liquid vapor pressure of benzene is 155 torr and the pure liquid vapor pressure of chloroform is 333 torr, then what is the total vapor pressure at 30°C of a solution of 9.26 g of benzene (C6H6) and 4.26 g of chloroform...

12 years ago

I made a bobo, which may lead to some confusion. Here is my post revised: You don't need it. Just calculate the new molarity of the acid after addition of NaOH, and then determine the molarity of the acid in solution. How many moles of propionic acid are...

10 years ago

Is the following statement true: (x^4+6x^2+9)=x^2+3

10 years ago

For each integer n>1, let A(n) denote the sum of the integers from 1 to n. For example, A(100)=1+2+3+ +100=5,050. What is the value of A(200)? A.)10,100 B.)15,050 C.)15,150 D.)20,100 E.)21,500 I know that the best answer choice is D, but the explanation t...

10 years ago

In your first question, 1 mole of sodium carbonate=2 moles of sodium=1 mole of carbon =3 moles oxygen. Take the moles for each of the components in sodium carbonate and multiply them by their respective molecular weights e.g. 3 moles of oxygen* 15.999g/mo...

12 years ago

G.P.E.=mgh=(2Kg)(9.8m/s^2)(15m)

12 years ago

Not sure, but I'll take a crack at it since no one else answered the question. KE=Force of Friction * distance. 1/2(MV^2)=mg *U*d= 1/2[(69,990Kg)(9.86m/s)^2 =(69,990Kg) (9.8m/s^2) *(0.002) *d. Masses cancel out, so the equation should be written as 1/2(9....

12 years ago

Ethylene has a triple bond composed of a pi and sigma bonds.

12 years ago

Ethene has a double bond between the carbons. The formula is C2H4, not C2H2;ethylene's formula is C2H2. 150g/28.05g/mole will give you the number of moles of ethene. Since the ratio between ethene and H2 is 1 to 4, multiply the number of moles of ethene b...

12 years ago

Correction, you have to subtract the grams of HCL from the total weight before calculating molality.

12 years ago

Did not know that you were posting an answer.

12 years ago

Assume 12 moles of HCL per liter: To solve for the molarity first, compute the total weight of the solution. Since, molarity is equal to moles/liter, assume that you have a total volume of 1L. 1L converted to mL is equal to 1.00 x10 ^3 mL. This multiplied...

12 years ago

Got it. Should have just done the math.

12 years ago

The Sum of Forces going down the ramp is equal to mg*sin*(theta). Mass * Acceleration = mg*sin (theta). since the masses are equal for both sides of the equation, you can write the equation as acceleration = g* sin (theta). and sove for the acceleration.

12 years ago

You would dilute the solution using MV=MV. Since you already have 1L of a 1M solution, you need to use the equation to calculate 0.1M. The answer will be 100L solution but you will only need to add 99L of H2O for every 1L of the solution. You will get 100...

12 years ago

Find the Density, which is equal to mass/volume, and use the equation density of the block/ density of water. If the density of the block is lower than water, then it will float, if not then it will sink or be submerged. To calculate the density of the bl...

12 years ago

Sorry, it should read 10L, not 100L and 9L not 99L. Also, DrBob22 is right you can boil/distill 50mL of water, but only if they do not have the same boiling point, but the answer is to add 9L not 10L.

12 years ago

I believe B,C, and D are correct but not A. gauge pressure is = Density*gravity*depth, which comes out to be 9800 PA. This isn't anywhere close to 10% of atmospheric pressure.

12 years ago

You are correct.

12 years ago

Since know one has answered this question, I will give it a try. But hopefully someone checks my work because I am a little tired. For Car A, Vi=0, a=5m/s^2, and t=?. For Car B, Vi=45m/s, Vf=45m/s, a=0, and t=?. Using two of the kinematic equations, 1/2(V...

12 years ago

Solve for the number of moles (n) using PV=nRT. R = 0.0821 liter·atm/mol·K, T= 31.0 +273K, P=1.11, V=7.10L. Rearrange the equation to give you n=PV/RT and plug in your values (n=[(1.11 atm)(7.10L)]/[(0.0821 liter·atm/mol·K)(31.0 +273.15K)]. Once you solve...

12 years ago

Not sure, but if since pressure in volume are inversely related you should see an increase in the pressure. so if volume decreased by 7/8, the pressure should increase by 7/8.

12 years ago

Just a question, how do you get 8x the initial pressure when it decreased by 7/8?

12 years ago

Dr. Bob22 and I disagreed, but use MV=MV to solve for the volume that you need, but first convert mL to L. V=[(3.00M)(0.037L)]/(0.500M). Remember, you already have an initial volume of 37mL or 0.037L, so subtract 0.037L from the answer that you get for V...

12 years ago

The time that it takes the ball to travel in the x-direction is the same amount of time that the ball takes to travel in the y-direction. Since you know the velocity of the ball and the distance, use D=V*T and solve for time (T). Once you solve for t, use...

12 years ago

The time (T) that it takes the spyglass to go in the x-direction is the same amount of time that it takes to travel in the y-direction. Since in the Y-direction the initial velocity is 0 and acceleration is equal to gravity (9.8m/s^2), use the equation D=...

12 years ago

Im not sure, but I believe that they will not. The larger the radius, the smaller the acceleration. Centripetal acceleration = V^2/r, so the runners in the outer lanes will have a smaller centripetal acceleration.

12 years ago

impulse momentum = Ft=M*Velocity. (0.484Kg)(9.1m/s)/0.247s should give you the Force (F).

12 years ago

Hopefully someone else comes along and checks this, but I'll give it a try. First convert all units of volume from mL to L and multiply them by their respective concentrations, which are given to you in molarity to find the number of moles. e.g. 25ml=0.02...

12 years ago

Vi=0 in the Y-direction of the bag going down, a=g=9.8m/s^2, d=40m. Even if it is rising at 5m/s, the velocity going down will not no be affected by the velocity going up. Since the velocity is 0, initially, and it accelerates down at a rate of 9.8m/s^2,...

12 years ago

Sorry, I forgot to convert everything back to molarity before plugging back in the values.

12 years ago

15 N is mass *acceleration. In this case, acceleration= gravity.

12 years ago

Excuse my typos as well.

12 years ago

65m^2/6.5m= Width. Report the answer as the number you get when dividing with only one m. Answer = __m

12 years ago

mass of silver/density of silver = volume of silver volume of silver + volume of water = total volume

12 years ago

mass of silver/density of silver = volume of silver volume of silver + volume of water = total volume

12 years ago

I believe the answer is 1/2kx^2=Fd=10N(0.2m)=2J. Hopefully someone checks this.

12 years ago

* = multiplication Let X= Rosalie. The first equation should read as followed: (4/5)*X=56 Solve for X. Which should give you 70 DVDs. Let X=Elizabeth. The second equation should read as followed: (17/10)*X= 51 Solve for X. Which should give you 30 plants.

12 years ago

CaCl2 is the limiting reagent. 1 mole of CaCl2 =2 moles of AgNO3=2 moles of AgCl =1 mole of Ca(NO3)2. 1.50g of CaCl2/110.98 g/mol of CaCl2= number of moles of CaCl2 number of moles of CaCl2*(2 moles of AgCl/1 mole of CaCl2) * 143.32 g of AgCl*mole-1= mass...

12 years ago

18g of H2O or one mole of H20.

12 years ago

Double check that. Are you sure that it is 1J?

12 years ago

0.315*254.6g= Mass of CaCl2 254.6g-Mass of CaCl2=Mass of H2O

12 years ago

That is a lab question that can not be answered by anyone unless you provide data.

12 years ago

It depends on what the initial genotypes were, but lets use Mendel's experiment to work this out. Lets say that the genotypes for the yellow seeds are YY and GG for the green ones for the parental generation. You have to show two letters, with each letter...

12 years ago

Use D=R*T=(745km/h)(3.3h) or (89km/h)(3.3h) if you want to know the distance for Car B.

12 years ago

1 atom =2.28E-22 g and 182mg=0.182g 0.182g*(1 atom/2.28E-22 g)= number of barium atoms.

12 years ago

D/R=T=(435m/s)/(253m)= time in s

12 years ago

look at your other post to see how to do this.

12 years ago

look at your other post to see how to do this.

12 years ago

You are correct for all of the except 6. The answer is d, all of the above.

12 years ago

{(12.7g/164.09g* mole-1)/ 0.1L}=Molarity

12 years ago

255m+(4.8m/s)*(88s)= displacement in meters.

12 years ago

I'm glad I wasn't the only one confused by the initial post.

12 years ago

(3.3cm^3)*(10^-6 m^3/1cm^3)=3.3 x10^-6 M^3 Not really chemistry, but math.

12 years ago

I believe its products - reactants, but I am not sure. maybe Dr. Bob222 will come along and give you the right answer. 29.4- 828.6=-819.2kj/mol Exothermic reaction.

12 years ago

This seems like chemistry, not physics. Use the combined gas law PV/T=PV/T and solve for T. [(0.2 x10^5 Pa)(0.8 x10^5)]/27=T

12 years ago

I thought 50 dB as well.

12 years ago

opps, sorry about the rearranging of the formula and she is right you have to convert to kelvins before doing the math.

12 years ago

I got 32.1 degrees. The problem worked out should read 0.532=sin(theta) sin-1 (0.532)=theta 32.1 degrees=theta

12 years ago

I'm not sure what, "11„aC" means, but if it is celsius then 11+273.15K=284.15K

12 years ago

See other post.

12 years ago

I apologize, I should have caught 2 as well. Plasma carries waste to the kidneys for excretion.

12 years ago

12 moles of H20 6 moles of NO 3 moles of Cu=4 moles of H2O=2 moles NO 9 mol of Cu*( 4 mol of H20/3 mol of Cu) = 12 moles of H2O 9 mol of Cu*( 2 mol of NO/3 mol of Cu) = 6 moles of NO

12 years ago

4NH3 + 3O2----> 2N2 +6H2O 4 mol of NH3=3 mol of O2=2 mol of N2=6 mol of H20 0.23 mol of NH3 *( 3 mol of O2/4 mol of NH3) = # of moles of O2 5 mol of O2 *( 2 mol of N2/3 mol of O2) = # of moles of N2

12 years ago

24 moles of CO2 *(2 moles of C2H6/4 moles of CO2) =12 moles of C2H6

12 years ago

The reaction is not balanced. First balance the reaction before attempting to solve, which I have already done for you. 3C2H3O2H+AL(OH)3----->AL(C2H3O2)3+3H2O 12 mols of C2H3O2H *( 1 mol of AL(C2H3O2)3/3 mols of C2H3O2H)= 4 moles of AL(C2H3O2)3

12 years ago

38.7% K =38.7g of K, 13.9% N= 13.9g of N, and 47.4% O =47.4g of O 38.7g of K*(1 mole of K/39.1g of K)=0.990 moles of K 13.9g of N*(1 mole of N/14.0g of N)=0.993 moles of N 47.4g of O*(1 mole of O/16.0g of O)=2.96 moles of O Take the lowest number of moles...

12 years ago

I left a note for you concerning your 1J calculation for physics.

12 years ago

Look at the your other posts for explanations. 1 mol of HCl*(CaCl2/2 mol of HCl)= 0.5 mol of CaCl2 5.5 mol of CaCO3*(1 mol of CaCl2/1 mol of CaCO3)= 5.5 mol of CaCO3

12 years ago

Okay lets give this a try. Imagine that you have a kennel and a small dog. Lets think about the kennel as the system and the dog as our energy source inside the kennel. The dog has a mass of, lets say 5kg. You lock the kennel with the dog in it. Another d...

12 years ago

You only have to solve for the mass; everything else is irrelevant to the answer. I hate it when teachers give you a bunch of extra information that you do not need to solve a straight forward problem. Density=mass/volume So, solve for mass density *volum...

12 years ago

The CH3, H, and OH group are connected to the structure I tried to type in the middle of this mess. The top CH3 goes with the fourth carbon (a covalent bond) from the left, the OH goes with the third carbon from the left, and the hydrogen goes with the fi...

12 years ago

The IR shows a bird wing at about 3500, so we know we have an OH group, and the degree of unsaturation is 2, so we have 2 double bonds or a triple bond. I am no where near positive, but I believe that the answer is H I CH3-C=C I I CH3-C=C CH3 I I H OH Thi...

12 years ago

The IR shows a bird wing at about 3500, so we know we have an OH group, and the degree of unsaturation is 2, so we have 2 double bonds or a triple bond. I am no where near positive, but I believe that the answer is CH3 CH3--CH=C--C=C--CH3 OH H This accoun...

12 years ago

D of Unsaturation =[(2 +(2 x number of carbons(6))-12]=2

12 years ago

your correct.

12 years ago

Like I said I'm not sure, but it looks like this may be 2,3-dimethyl-cyclopropanol. This would account for the splitting problem, but since I am not sure I wouldn't bet money on it.

12 years ago

This gave me a headache. I'm sorry, 1,2,- trimethyl-cyclopropanol.

12 years ago

1,23,- trimethyl-cyclopropanol.

12 years ago

This is bugging me, because I'm not sure. the peaks for d and e should show splitting, but they don't. The only structure that I can think of is 2,3,3-trimethyl-cyclopropanol. Hopefully someone else comes along and is of some assistance. Post the right an...

12 years ago

1 to 2 degrees celsius per minute. If it is too fast, you can overestimate the melting point, and if you are trying to determine the range, the range wil be narrower then it would be at a slow temperature.

12 years ago

The end of the sentence in the above post should say slower temperature rate.

12 years ago

14-5.75= pOH pOH=8.25 Since pOH=-log[OH-] 10^(-8.25)=OH-=5.62 x10^-9M That's what I got.

12 years ago

If you are asking what is the dissociation constant (Kb) for HPO₄², you want be able to solve for it with the information given; you have to look up the Ka for HPO₄² in a book. Ka for HPO₄²=4.2 x10^-13 Kw= Ka*Kb Solving for Kb, Kb=Kw/Ka= 1 x 10^-14/4.2 x1...

12 years ago

Okay, it just bugged me. I think I solved it, but two of the peaks for protons in the H NMR spectrum weren't split like I thought they would be, and so I wasn't sure when I gave the individual a final answer after several attempts.

12 years ago

With that being said, Kb=Kw/Ka= 1 x 10^-14/6.2 x10^-8 =1.6 x10^-7

12 years ago

Yes, the way your reference is set-up. Remember, Kw= Ka*Kb. if you want to know the Kb, you need to know the Kw and Ka. If you want to know the Kb, you need to know the Ka and Kw.

12 years ago

Its c, I used the wrong Ka value when I initially did it.

12 years ago

Strong bronsted lowry acids are H+ donors, bases are proton acceptors. Lewis acids are electron pair acceptors, and Lewis bases are electron pair donors.

12 years ago

But saying completely ionized is not necessarily correct. A strong acid such as HCl will be completely ionized in the presence of a weak or a strong base, but a strong acid like H3PO4 will give up the its first proton readily in a solution with a weak or...

12 years ago

B. K3PO4.

12 years ago

I'm actually a biochemist, I just haven't been immersed in some of this stuff in a while. My last post should read conjugate base not acid. Sorry for that, I'm a little prone to typos and brain farts when I'm a little tired.

12 years ago

Should have read (253m/435m/s)=t

12 years ago

Although all of H3PO4 is completely ionized (i.e, -H2PO4,) it can not give up the rest of its H+ readily.

12 years ago

If the M in 3.26m is molarity, then the answer is 3.26 moles. Molarity is the number of moles of solute/liter of solvent.

12 years ago

A. False. Under steady state conditions, the concentrations of intermediates stay the same while the concentrations of the SUBSTRATE and PRODUCT change. Steady state conditions refer to the steady concentrations of of the ES complex not the concentration...

12 years ago

From your other posts, I see that you may not have taken organic chemistry yet. Most universities require that you take and pass organic chemistry before you can take biochemistry. If UCI allows you to take biochemistry before taken and passing organic ch...

12 years ago

Molarity of H2SO4=9.0 20g of NaOH/39.997 g/mol= mols of NaOH Since Molarity=moles/Liter, mols of NaOH/Molarity= volume in Liters of H2SO4

12 years ago

37%=37g of HCl 100 total g of solution-37g of HCl=63g of solvent=0.063Kg of solvent 37g of HCl/36.5 g/mol=mols of HCl Since total weight is 100g and density=mass/volume, solve for volume mass/density=volume=100g/1.19g/mL= volume of solution convert volume...

12 years ago

Be careful here. Setup is correct, but molarity = moles/volume in liters not milliliters. 20 x10^-3L *(0.0080)= moles of sodium chloride solving for volume, moles/molarity = volume of silver nitrate= moles of sodium chloride/molarity of silver nitrate

12 years ago

and when you think of strong bronsted lowry acid you think of strong proton donors.

12 years ago

Au3+(aq) + 3e --> Au(s) E=+1.42 Cr3+ (aq) + 3e -->Cr(aq) E= -0.74 V Since the standard-reduction potential is positive for Au, the reaction should occur at the cathode and the reaction for Cr3 will occur at the anode. E(cell)=E(cathode)-E(anode)= 1.42-(-0...

12 years ago

Sorry, it's Cr3+ (aq) + e -->Cr2+(aq) E= -0.41 V not Cr3+ (aq) + 3e -->Cr(aq) E= -0.74 V E(cell)=E(cathode)-E(anode)= 1.42-(-0.41)= 2.83V

12 years ago

1.83V not 2.83V

12 years ago