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Devron
Questions (7)
For each integer n>1, let A(n) denote the sum of the integers from 1 to n. For example, A(100)=1+2+3+ +100=5,050. What is the
4 answers
2,626 views
Is the following statement true:
(x^4+6x^2+9)=x^2+3
8 answers
507 views
I made a bobo, which may lead to some confusion.
Here is my post revised: You don't need it. Just calculate the new molarity of
1 answer
590 views
When you get a chance:
If the pure liquid vapor pressure of benzene is 155 torr and the pure liquid vapor pressure of chloroform
5 answers
893 views
I agree with 0.0918 mols C and 0.137 mols H but not the formula.
0.137/0.0918 = about 1.5; is that C2H3? And the balanced
6 answers
451 views
I believe that you are correct because you have more experience in G-chem then I have. But how does doubling the reaction rate
5 answers
430 views
what is this compound, it has a mf of c6h12o i. imgur. com/gCgw0Hi. png
What may be the structure from the IR and H NMR data?
3 answers
571 views
Answers (1,040)
i used to come back every year to see if you were still here. I wonder how you are doing. I'm now a college student lol
Keq=1.8 x 10^-16 ====> determined experimentally and is accepted as the value at 25.0 C Assuming 1L of water is 1000g and the molecular weight of water is 18.02g/mole....... 1000g/L*(mole/18.02g)=55.5 M H2O ------------> H^+ + OH^- Let X =H^+=OH^- Keq=1.8
I would put haploid for the first blank and diploid for the second blank.
Heat: PCR reactions are heat intensive processes, which require a polymerase that is able to withstand the heat. Taq polymerase is what is usually used in PCR reactions.
Thanks
Thanks, so this falls under induction by reasoning, if I'm not mistaken?
That is correct. 200 + [0.15 * (2,500-1,000)] = ?
200 + (0.15 * 2,500) = ?
a.The monomers that make up a protein vary whereas the monomers that make up a complex carbohydrate are all the same. --This is mostly true, but I would suggest that you give a couple of examples, such as fatty acids, or a short truncated protein.
Things to keep in mind: Molarity=Moles/Volume (L) HNO3=63.01g/mol 69.5%=0.695 and 1cm^3=1mL=10^-3L Convert Density from g/cm^3 to g/L: 1.42g/cm3*(1cm^3/10^-3L)=1420g/L Calculate the amount of pure acid: 1.420g/L*(0.695)= mass of pure HNO3 in g/L Since the
Got it. I was totally overthinking this.
I know that, which is why I thought the answer was no, but then I was told that the answer was yes. I couldn't simplify nor reason it any further than what I have submitted. If you can show how to do it, it would be greatly appreciated; the problem is kind
I thought is was no. When asked this question by someone, I could not get the left side to look like the right. x^2+ x(6)^1/2+3=x^2 +3 How does this simplify any further?
Is the following statement true: (x^4+6x^2+9)^1/2=x^2+3
The pull of electrons is the main reason. The pull of the lone electron of hydrogen by oxygen shortens bond length; this is easily seen by looking at the electronegativity difference between oxygen and hydrogen. Although alcohol also contains a OH bond,
I just noticed that I messed up. D is an answer that shouldn't have eliminated, and to be honest, I believe that it is the best answer choice.
First, determine the molarity of KHC2O4: 0.717g*(1 mol/128.12g)=moles of KHC2O4 18.47 mL=0.01847L Molarity of KHC2O4=moles of KHC2O4/0.01847L The reaction is a 1 mole to 1 mole reaction. Therefore, moles of KHC2O4=moles of NaOH. So, Molarity of
I'm not sure, but I do not think that a reaction would occur. ALCl3 usually acts as a catalyst, and would just form an ionic bond with the oxygen on the carbonyl of the compound; there isn't another reactant to form some other compound.
I initially made the same mistake, which confused me a little. I reread the question and saw that the questioner and I, both, may have initially overthought the question. --Best
To the questioner: I apologize about the typos. I meant to say solve for Delta*G and not just Delta. My post should have said the following: DeltaG=DeltaH-DeltaS*T Where DeltaH=-220kJ/mol DeltaS=-136.76J/K=-0.13676kJ/K T=426K and DeltaG=???
I hope someone validates this answer since I don't play around with these concepts all of the time, but here is my response. The force that the block exerts down the ramp is the following: Fof block=mg*Sin(30) Fof block=(4.0kg)*(9.8m/s^2)*(0.5)=19.6N Force
The key part of the equation states that ASSUME that DeltaS and DeltaH DOESN'T Change much, meaning that it is safe to plug and chug. ***To the questioner: change -136.76J/K to kJ, which should be -0.13676kJ/K
DeltaG=DeltaH-DeltaS*T Where DeltaH=-220kJ/mol DeltaS=-136.76kJ/K T=426K and Delta=????
It would increase the rate of the reaction. Looking at the equation should allow you to notice this. In general there are three factors that can affect the rate of a reaction: 1.) reactant concentrations 2.) catalysts 3.) temperature
You can use an equation or you could just do it intuitively; I choose to do this one intuitively. 1.0mg =12 hrs 2.0mg=10 hrs 4.0mg=8 hrs 8.0mg= 6hrs 16.0mg=4hrs 32.0mg=2hr 64.0mg=0hrs So, you will initially need 64.0mg of 55Cr to have a minimum of 1.0mg
I think that you need more information then what you are providing for someone to be of any help.
Use the following equation: Ln(k2/k1)=Ea/R[(1/T1)-(1/T2)] Where k1=0.0796 M−1*s−1 k2=0.0815 M−1*s−1 R=8.314 J/mol K. T1=273+737=1010K T2=273+947=1220K and Ea=???? Solve for Ea: Ea={R*[Ln(k1/k2)]}/[(1/T1)-(1/T2)]
The purpose of the endocrine system, which secretes hormones, is to control growth and development. Which of these answer choices best fits that description? I will eliminate two answers for you -- answer choices C and D-- to give you a 50/50 chance
I apologize about that. I should have thought about it for more than 3 seconds. The answer is in the directions: the puck travels only one-half the distance Conservation of mechanical energy says that Work=kinetic energy F*d=1/2mv^2 m*a*d=1/2mv^2 masses
I wouldn't know how to solve the problem either because you are missing some information.
V3=9.82m/s
I didn't fully read this question; I was wondering what Dr.Bob222 did. He is correct: 4.0mL of of Cl2 will be used meaning that there will be no Cl2 left at the end of the reaction, but 3.0mL of H2 gas will be left after the reaction is complete. However,
Use the following relationship: M1V1 +M2V2= M3V3 Where M1=5.00kg V1=12.0m/s M2=6.00kg V2=8.00m/s M3=5.00kg+6.00kg=11.00kg and V3=??? Solve for V3: (5.00kg*12.0m/s)+(6.00kg*8.00m/s)=(11.00kg)V3 V3=108kg*m/s/11.00kg V3=9.82 N s
I meant to say that the answer to part 2 isn't the answer to part 1.
I agree with DrBob222 and then I don't agree with him: I agree that the 2nd part that he gave you in his last point is correct, but the answer to part 2 isn't the answer to part 2. I agree that it should because adding these two concentrations of acid
The same way that I showed you how to do the other one, but just convert 8.08g of H2 to moles: 8.08g of H2*(1 mole/2.02g)=??? moles
14 H^+ + 2 Mn^2+ + 5 NaBiO3 --->5 Bi^3+ + 2 MnO4^- + 5 Na^+ + 7 H2O Here is the the balanced reaction (Oxidation and Reduction) 34.2MgSO4=0.0342g of MgSO4 0.0342g of MgSO4*(1 mole/120.366 g)= moles of MgSO4 The equation shows that 2 MnSO4 moles=5 moles of
I wouldn't tackled it this way, and you are free to not use what I am telling you because I can not be 100% positive about the answer. However, I would go this route: q=mct where q=44,000 kJ=4.4 x 10^4 kJ=4.4 x 10^7 J c=8.37 J/g*C t=110 C-95 C=15 C and
Assuming O2 is in excess: 2 moles of MgO=2 moles of Mg=1 moles of O2 So, 4 moles of Mg*(-1203kJ/2 moles of Mg)=???
I am not sure, and someone can come along after I am done and check what I am telling you, but I believe you are missing some information like the temperature change. The question seems to be incomplete.
The reaction is as followed: H2 + Cl2 ----> 2HCl You can treat this as a limiting reagent problem, where Cl2 is the limiting reagent. 1 mole of Cl2=2 moles of HCl or 1mL of Cl2= 2 mL of HCl 4.0mL of Cl2*(2 mL of HCl/Cl2)= 8mL of HCl (g)
The first question asks for the MOLARITY of the solution after adding the two together; the second question asks for the molarity using the DENSITY. You will get two different answers. Also, the acid that is given is H2SO4 and not HCl. The molecular weight
Because the virus doesn't affect the rest of the cell types that it targets until a stress or an environmental factor causes reproduction and lysis; it remains dormant until it receives it's que to begin.
First, convert mL to L: 20mL=0.0200L and 30.0mL=0.0300L Solve for moles: M=moles/Volume (L) so, moles=M*Volume(L) New Molarity=Total moles/Total Volume M=[(0.0200L)*(3.0 M)+(0.0300L)*(2.0M)]/(0.0200L+0.0300L)
HCl is a strong acid so, determine the pH: pH=-log[HCl] pH+pOH=14 14-pH=pOH Since pOH=-log[OH^-] 10^-(pOH)=[OH]
I don't see questions 1 and 2, but if you are referring to questions 4 and 5, then I believe that answer choice A is the best answer choice for number 4 and I agree with your answer choice for number five as well.
Write out the reaction: ZN + 2 HCl --> ZNCl2 + H2 Covert g of H2 gas produced to moles: 0.15g of H2*(1 mole/2.016g)= moles of H2 moles of H2=moles of Zn moles of Zn*(65.37g/mol)= g of Zn Answer contains two significant figures Conversely, this could have
3^4=??????
if the volumes of the weak acid and its conjugate base are equal than the pH=pka of the solution. You know this by looking at the Henderson–Hasselbalch equation. pH=pka+log[A^-]/[HA] Where A^-=NaNO2 and HA= HNO2 Since the concentrations are equal, the
ATP is the energy source for all cells, so that answer is ruled out. C is also ruled out because although it is a neurotransmitter, it is activated to usually cause an emotional response; Glycine is one of the simple amino acids that doesn't act on taste
