Asked by tyneisha
Determine the moles of aluminum acetate,AL(C2H3O2)3,that can be made if you do this reaction with 12 moles of acetic acid (C2H3O2H)
C2H3O2H+AL(OH)3->AL(C2H3O2)3+3H2O
C2H3O2H+AL(OH)3->AL(C2H3O2)3+3H2O
Answers
Answered by
Devron
The reaction is not balanced. First balance the reaction before attempting to solve, which I have already done for you.
3C2H3O2H+AL(OH)3----->AL(C2H3O2)3+3H2O
12 mols of C2H3O2H *( 1 mol of AL(C2H3O2)3/3 mols of C2H3O2H)= 4 moles of AL(C2H3O2)3
3C2H3O2H+AL(OH)3----->AL(C2H3O2)3+3H2O
12 mols of C2H3O2H *( 1 mol of AL(C2H3O2)3/3 mols of C2H3O2H)= 4 moles of AL(C2H3O2)3
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