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How many Moles of Aluminum are needed to completely react with the 1.50 moles of copper 2 sulfate you collected. ( equation: 2Al + 3CuSO4 —> Al2(SO4)3 + 3Cu
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Answered by
DrBob222
2Al + 3CuSO4 —> Al2(SO4)3 + 3Cu
Did you collect 1.50 mols CuSO4 and use that in this reaction? Are you asking how many mols Al are needed to react with 1.50 mols CuSO4? I assume that's the question. Look at the coefficients. They tell you that 2 mols Al will react with 3 mols CuSO4; therefore,
1.50 mols CuSO4 x ( 2 mols Al/3 mols CuSO4) = 1.50 x 2/3 = ?
Did you collect 1.50 mols CuSO4 and use that in this reaction? Are you asking how many mols Al are needed to react with 1.50 mols CuSO4? I assume that's the question. Look at the coefficients. They tell you that 2 mols Al will react with 3 mols CuSO4; therefore,
1.50 mols CuSO4 x ( 2 mols Al/3 mols CuSO4) = 1.50 x 2/3 = ?
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