The [OH-] of a solution with a PH 5.75 is

Question

is it 5.6*10-9M?

Answer 1

14-5.75= pOH
pOH=8.25

Since pOH=-log[OH-]

10^(-8.25)=OH-=5.62 x10^-9M

That's what I got.

Answer 2

Aww thanks soo much buddy :)