Asked by Shreya

The [OH-] of a solution with a PH 5.75 is

is it 5.6*10-9M?
Answered by Devron
14-5.75= pOH
pOH=8.25


Since pOH=-log[OH-]

10^(-8.25)=OH-=5.62 x10^-9M


That's what I got.
Answered by Shreya
Aww thanks soo much buddy :)
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