Asked by Vic

A 10.-newton force is required to hold a
stretched spring 0.20 meter from its rest position. What is the potential energy stored in the
stretched spring?
Answered by Devron
I believe the answer is 1/2kx^2=Fd=10N(0.2m)=2J. Hopefully someone checks this.
Answered by Vic
It's actually 1J. You forgot to divide by one! Thank you!
Answered by Devron
Double check that. Are you sure that it is 1J?


Answered by Erin
It's definitly 1J
Answered by Adrianna
Guys it is 1 J
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