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The reduction potentials for the species involved in an electrochemical cell are as follows: M+ + e– ==> M is 0.10 V J+ + e– ==...Asked by Tom
The reduction potentials for the species involved in an electrochemical cell are as follows:
M+ + e– => M is 0.20 V
J+ + e– => J is 1.00 V.
All solutions are 1.00 M and J+ J is connected to M+ M
What is E*cell (in V)?
* is a 0. It stands for E not
M+ + e– => M is 0.20 V
J+ + e– => J is 1.00 V.
All solutions are 1.00 M and J+ J is connected to M+ M
What is E*cell (in V)?
* is a 0. It stands for E not
Answers
Answered by
GK
Since the solutions are 1.0M, E(cell) equals the difference of the standard reduction potentials. In more complicated cases (molar concentrations not equal to 1.0M) you would have to use the Nernst Equation.
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