Question
The reduction potentials for the species involved in an electrochemical cell are as follows:
M+ + eā ==> M is 0.10 V
J+ + eā ==> J is 0.30 V.
All solutions are 1.00 M and J+/J is connected to M+/M.
1. What is Ecell (in V)?
2. Which species is easier to oxidize?
3. The electrons flow from __ (M or J) to __ (M or J).
I think #3 is M to J
M+ + eā ==> M is 0.10 V
J+ + eā ==> J is 0.30 V.
All solutions are 1.00 M and J+/J is connected to M+/M.
1. What is Ecell (in V)?
2. Which species is easier to oxidize?
3. The electrons flow from __ (M or J) to __ (M or J).
I think #3 is M to J
Answers
DrBob222
#3 is M to J, I believe.
1. Pick the largest negative voltage, turn that reaction around and change the sign. Add in the other reaction and add the voltages.
2. Write both reactions as oxidations. The one with the larger positive number is the easier to oxidize.
1. Pick the largest negative voltage, turn that reaction around and change the sign. Add in the other reaction and add the voltages.
2. Write both reactions as oxidations. The one with the larger positive number is the easier to oxidize.