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Damon
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U=(10i+15j)m/s Traject What U And V
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I bet the student had a typo.
16 and 5 are also between 3 and 17
No way 3 is not between 3 and 17 16, 8 and 5 are
first the x value: x = 2 to x = 3 is to midpoint,so one more to the end so x = 3+1 = 4 now the y value y = 4 to y = -1 is down 5 to midpoint so go 5 more down to y = -6 so agree with the Bot ( 4 , -6 )
U=(10i+15j)m/s Traject What U And V
Well, if you were a boat navigator you would use the 45 degree trick. Measure that distance from you to that road. That distance, d, should be perpendicular to the road. Now look 45 degrees right (or left). The distance along the road to that point on the
first 250 km/hr = 250,000 meters / 3600 seconds = V acceleration = rate of change of velocity = change in V / change in time = (250,000/3600) / 2.2 meters/ second^2
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second one Again the mass does not matter (1/2) m v^2 = m g h v = sqrt (2 g h) (remember that)
his mass has nothing to do with it. Vi = 4.7 how long to reach top? v = Vi - g t 0 = 4.7 - 9.81 t t = .479 seconds up H = 3.8 + Vi t - 4.9 t^2 h = 3.8 + 4.7(.479) - 4.9 (.479^2) h = 3.8 + 2.25 - 1.12 h = 4.93 meters stopped above ground, falls from there
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y distance = 40 x distance = 30 d = sqrt (40^2 + 30^2) the hypotenuse = 50 I suspect (3,4,5 triangle)
I read even numbers so increased by 2 each time. Just do increase by 1 same system, same answer
call distance Ma to C = n law of cosines n^2 = 74^2 + 42^2 - 2*74*42 cos 45 n^2 = 5476 + 1764 - 4395 = 2844 n = 53.3 km then sin Ma/42 = sin 45/n sin Ma = .557 Ma = 33.8 so direction from Ma to C = East + 45 + 33.8 = east + 78.8 or 169 clockwise from
Tricky If it goes in 10 cm, the wood on the left is pushed 1 cm and the wood on the right is pushed 1 cm. Therefore I would say the velocity of the wood on each side of the wedge was 1/10 times the velocity of the wedge. 30 * 10 = 300 Newtons
Vx = (36 - 6t)^.5 at t = 1, it is sqrt(30) Vy = 4t at t = 1, it is 4 so |V| at 1 = sqrt(46) Ax = .5 (36-6t)^-.5 * (-6) = -3/sqrt 30 = -.55 at t = 1 Ay = 4 The velocity is increasing fast, yes, C
LOL, usually there are two answers, going east or going west. However this time 49 + 131 = 180 degrees Exactly :) halfway around so what is the circumference at 36 North latitude c = Cat equator * cos (latitude) c = 2 pi (6370) * cos 36 = 32,380 We want
