Asked by Ashley
Please explain how to do this problem:
5 + 3 x 2 + (4+2)=
I did 5+3=8 x2+ 16 +6=22
did I do this correctly?
Thank you...
5 + 3 x 2 + (4+2)=
I did 5+3=8 x2+ 16 +6=22
did I do this correctly?
Thank you...
Answers
Answered by
Mike
i got 17
Answered by
Mack
no.
Answered by
DrBob222
You may NOT add 5 and 3x^2.
<b>
5 + 3 x 2 + (4+2)=
I assume you mean for this to be
5 + 3x^2 + (4+2) = and I'll go from there.
3x^2 + 11 =
3x^2 = -11
x^2 = -11/3
x = sqrt (-11/3)</b>
<b>
5 + 3 x 2 + (4+2)=
I assume you mean for this to be
5 + 3x^2 + (4+2) = and I'll go from there.
3x^2 + 11 =
3x^2 = -11
x^2 = -11/3
x = sqrt (-11/3)</b>
Answered by
Damon
5 + 3 x 2 + (4+2)
5 + 3*2 + 6 Do in parentheses first
5 + 6 + 6 multiply or divide
now add
I also get 17
BUT perhaps you left a parenthesis out?
IF you really had
(5+3)*2 + (4+2)
THEN
(8)*2 + 6
=16 +6
=22
5 + 3*2 + 6 Do in parentheses first
5 + 6 + 6 multiply or divide
now add
I also get 17
BUT perhaps you left a parenthesis out?
IF you really had
(5+3)*2 + (4+2)
THEN
(8)*2 + 6
=16 +6
=22
Answered by
Mack
5+3=8 right?
now you solved what 5+3 equaled.
Now your problem reads 8x2+(4+2)
Next you solve what 8x2 equales and what 4+2 equales.
and when you add those two answers together what do you get?
now you solved what 5+3 equaled.
Now your problem reads 8x2+(4+2)
Next you solve what 8x2 equales and what 4+2 equales.
and when you add those two answers together what do you get?
Answered by
Damon
I assume she used x for times and not a variable name based on her earlier postings, but I could easily be wrong.
Really for that reason it is a good idea to use * for "multiply" Ashley
Really for that reason it is a good idea to use * for "multiply" Ashley
Answered by
Ashley
you all are right, I was still confused but look above, I think I have it now...
Thanks for your help everyone!!!
Thanks for your help everyone!!!
Answered by
Mack
YOU'RE WELCOME!
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