Ask a New Question

Asked by Anonymous

given y=theta-cos theta and x=sin theta. Show that d^2x/dy^2 =sec^2 theta (tan theta + sec theta)
3 years ago

Answers

Answered by mathhelper
y = θ - cosθ and
x = sinθ

before I do this, confirm that this is what you actually meant,
and confirm you are not missing some trig operator in front of
that first θ
3 years ago
Answered by Muhindo
Yes I didn’t miss any trig operator
3 years ago

Related Questions

Interval 4sec(theta)(sec(theta)+tan(theta))d(theta) can someone help me start his problem? 1-2sin^2(theta/2)=2cos^2(theta/2)-1 sin theta/2cos theta/2=1/2 sine theta show the identiy and work r=8cos(theta)+5sin(theta), convert the polar equation into a rectangular equation and then complete... f(theta)= 4sec(theta)+ 2tan(theta), 0 less than theta less than 2pi. find all critical numbers show that sec theta(cosec theta) - cot theta = tan theta if 5sin theta + 12cos theta is equal to 13 find the value of tan theta Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation Xsin(theta)-Ysin(theta)=sqrtX^2+Y^2 and cos^2(theta)/a^2+sin^2(theta)/b^2=1/X^2+Y^2 then find correc... 3cos^2(theta)-3 = 5sin(theta)-2
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use