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Asked by aakash

Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation
11 years ago

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Answered by Steve
not sure what to do with

cos^2(theta)/a^2+sin^2(theta)/b^2

since it's part of no equation.
11 years ago
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Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation

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