Question
Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation
Answers
Steve
not sure what to do with
cos^2(theta)/a^2+sin^2(theta)/b^2
since it's part of no equation.
cos^2(theta)/a^2+sin^2(theta)/b^2
since it's part of no equation.