Asked by aakash
Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation
Answers
Answered by
Steve
not sure what to do with
cos^2(theta)/a^2+sin^2(theta)/b^2
since it's part of no equation.
cos^2(theta)/a^2+sin^2(theta)/b^2
since it's part of no equation.
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