Question

Interval 4sec(theta)(sec(theta)+tan(theta))d(theta)

can someone help me start his problem?

Answer 1

Interval, or integral?

I suggest you split it up into
4 sec^2 (theta)
+ 4 sin(theta)/cos^2(theta)

Answer 2

You can find the integral of the first one in a table of integrals. The second one is easy if you let u = cos theta and du = -sin theta dtheta

Answer 3

The integral of sec^2 is tan