Question
Suppose x=4sin(theta, for theta (-pie/2, pie/2). Rewrite(sqrt16-x^2)^3/x^3
(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)
(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)
Answers
sabrina
malachi has three tvs of: 25",27",32".
what the average size of malachi tvs?
what the average size of malachi tvs?
Steve
x = 4sinθ
sinθ = x/4
so, the other side is √(16-x^2)
√(16-x^2)/x = cotθ
[√(16-x^2)/x]^3 = cot^3(θ)
sinθ = x/4
so, the other side is √(16-x^2)
√(16-x^2)/x = cotθ
[√(16-x^2)/x]^3 = cot^3(θ)