Asked by nicky
3cos^2(theta)-3 = 5sin(theta)-2
Answers
Answered by
oobleck
3cos^2θ - 3 = 5sinθ - 2
3(1-sin^2θ) - 3 = 5sinθ - 2
3 - 3sin^2θ - 3 = 5sinθ - 2
3sin^2θ + 5sinθ - 2 = 0
(3sinθ-1)(sinθ+2) = 0
sinθ = 1/3 or -2
...
3(1-sin^2θ) - 3 = 5sinθ - 2
3 - 3sin^2θ - 3 = 5sinθ - 2
3sin^2θ + 5sinθ - 2 = 0
(3sinθ-1)(sinθ+2) = 0
sinθ = 1/3 or -2
...
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