Asked by Anonymous

A flowerpot falls from a windowsill 33.0 m above the sidewalk.
a) How much times does a passerby on the sidewalk below have to move out of the way before the flowerpot
hits the ground?
b) What is the flowerpot's velocity when it strikes the ground?

Answers

Answered by Damon
g = a = -9.81 m/s^2
v = 0 - 9.81 t
h = 33.0 + 0 t - 4.9 t^2
h = 0 at crash
4.9 t^2 = 33
t = 2.6 seconds to disaster
back to v = 0 -9.81 t
= - 9.81*2.6 , negative because downward like g
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