Question

A flowerpot falls from a windowsill 33.0 m above the sidewalk.
a) How much times does a passerby on the sidewalk below have to move out of the way before the flowerpot
hits the ground?
b) What is the flowerpot's velocity when it strikes the ground?

Answer 1

g = a = -9.81 m/s^2
v = 0 - 9.81 t
h = 33.0 + 0 t - 4.9 t^2
h = 0 at crash
4.9 t^2 = 33
t = 2.6 seconds to disaster
back to v = 0 -9.81 t
= - 9.81*2.6 , negative because downward like g