Asked by B
A flowerpot falls from a windowsill 155.0 m above the sidewalk. How fast is the flowerpot moving when it hits the ground?
Answers
Answered by
Anonymous
(1/2) m v^2 = m g h
so
v = sqrt ( 2 g h)
v = sqrt (2 * 9.81 * 155)
so
v = sqrt ( 2 g h)
v = sqrt (2 * 9.81 * 155)
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