Asked by Drew
A flowerpot falls off a windowsill and falls past the window below. It takes the pot 0.42 s to pass this window, which is 1.90 m high. How far is the top of the window below the windowsill from which the flower pot fell?
Answers
Answered by
drwls
Write equations for the time to reach the top and bottom of the window. There will be two unknowns: (1) unknown distance to from window top to windowsill above (h) and (2) time to reach the top of the window (t).
Solve the two equations in two unknowns.
(1/2) g t^2 = h
(1/2) g (t + 0.42)^2 = h + 1.9
h is easily eliminated by subtracting the first equation from the second.
g = 9.8 m/s^2
Solve for t fist and then use either of the two equations to compute h.
Solve the two equations in two unknowns.
(1/2) g t^2 = h
(1/2) g (t + 0.42)^2 = h + 1.9
h is easily eliminated by subtracting the first equation from the second.
g = 9.8 m/s^2
Solve for t fist and then use either of the two equations to compute h.
Answered by
Kate
1.04 m
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