Question
A flowerpot falls from a window sill 26.8 m above the sidewalk.
What is the velocity of the flowerpot when it strikes the ground? The acceleration of gravity is 9.81 m/s2 .
What is the velocity of the flowerpot when it strikes the ground? The acceleration of gravity is 9.81 m/s2 .
Answers
Henry
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*26.8 = 525.28
V = 22.92 m/s.
V^2 = 0 + 19.6*26.8 = 525.28
V = 22.92 m/s.
Anonymous
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