Asked by John

A flowerpot falls from a window sill 37.6 m above the sidewalk.
What is the velocity of the flowerpot when it strikes the ground? The acceleration of gravity is 9.81 m/s2.
Answer in units of m/s

Please show me the formula and steps i would use to solve this, Thanks!

Answers

Answered by Damon
v = a t = 9.81 t
d = (1/2) a t^2 = 4.905 t^2 = 37.6
so
t^2 = 7.67
t = 2.77 s

v = 9.81* 2.77 = 27.2 m/s
Answered by John
that's what i did but the computer is telling me it's wrong
Answered by Anonymous
thats wrong mate
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