Question
1. A flowerpot falls from a windowsill 25.0 m above the sidewalk.
a. how fast is the flowerpot moving when it strikes the ground?
dont i need to know the time it takes, what formula am i supposed to use for this? would 25 m be the displacement?
b. how much time does a passerby on the sidewalk below have to move out of the way before the flowerpot hits the ground?
please help!!
a. how fast is the flowerpot moving when it strikes the ground?
dont i need to know the time it takes, what formula am i supposed to use for this? would 25 m be the displacement?
b. how much time does a passerby on the sidewalk below have to move out of the way before the flowerpot hits the ground?
please help!!
Answers
(a)
Vf^2 = Vo^2 + 2gy
since Vo = 0,
Vf^2 = 2gy
Substitute and solve for Vf
(b)
y =(1/2) gt^2
Substitute and solve for t
Vf^2 = Vo^2 + 2gy
since Vo = 0,
Vf^2 = 2gy
Substitute and solve for Vf
(b)
y =(1/2) gt^2
Substitute and solve for t
wewt
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