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Damon

@Damon

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8/9 + (1/4) * 8/9 = 8/9 + 2/9 = 10/9 = 1 1/9
The cheetah and her cubs staying in one place for only four days helps keep the cubs safe from predators. If the cubs are safe they can grow and reproduce. The cheetah mothers also teach their Cubs to hunt, so the cubs can hunt their food and survive and
By the way, if you use a 24 hour (military or seagoing) clock, 11 + 6 = 17 17:00 is 5 pm
70 = 25 + 7.50 h 45 = 7.5 h h = six hours 11 to noon is one of the six hours, five are left so 5 pm
v = ds/dt = -32 t + 64 0 = -32 t + 64 t = 2 not 64
They asked for the maximum height That is when ds/dt = 0 In other words when the speed up stops
Let me see, I used feet a few years ago, like 60. v = ds/dt = -32 t + 64 a = -32 ft/second^2 = constant acceleration of gravity by the way max height when v = 0 (stops going up, not going down yet) t = 64/32 seconds
n >/= 10 is easy with my keyboard but put the = under the arrow.
time to slow down: Vi = 71.0 m/s average speed during slowing = 71/2 = 35.5 m/s 250 = 35.5 t t = 7.04 seconds to stop T now at 250 meters M now at 7.04*71 = 500 meters (twice as fast of course) after 5 second stop T still at 250 meters M now at 500 + 5*71
yes, meters times 1000 = millimeters
work out = 500 * 1.5 = 750 Joules work in = 1000 Joules so 750/1000 = 0.75 = 75%
30 < n < 35 31 32 33 34
So, no
https://www.mathsisfun.com/sets/domain-range-codomain.html
Huh?
Everything there is just a few hours earlier.
If you tried to copy and paste that does not work on this site. We can not see it.
that means there is a y for every value of x between −∞ and +∞ for example that would not be true for y = 7/ (x-1) because there is no y when x = 1
Looks like about $5 per guest :)
4*5 = 20 8*5 = 40 12*5= 60
sqrt 3 is irrational so there is no exact answer. It is about 1.732050808
Ich verstehe aber ich kenne sehr weinig Deutsch.
100 - 2 = 98% left 0.98 * 2.50 = 2.45
g = a = -9.81 m/s^2 v = 0 - 9.81 t h = 33.0 + 0 t - 4.9 t^2 h = 0 at crash 4.9 t^2 = 33 t = 2.6 seconds to disaster back to v = 0 -9.81 t = - 9.81*2.6 , negative because downward like g
now for 1/2 + 1/4 you want all leprecauns, or in this case quarters. 2/4 + 1/4 = 3/4 but you knew that
So in my opinion 5/10-3/10 = 2/10 which is 1/5 Just like 5 leprecauns - 3 leprecauns = 2 leprecauns or whatever
You are welcome.
Just get the same denominator and see which numerator is bigger.
Where is your work? If you tried I bet you could subtract 3 from 5.
5/8 is 10/16 which is
y = 10 x + 20
n + (n+12) = 74 2 n + 12 = 74 2n = 62 etc
mass = force / acceleration = weight / g = 20 /10 kg
I am just plain not going to answer that. Which do you think is correct?
is 1/9 over 1/2 or under? under is it closer to 0 or to 1/2 ? well 1/2 is 4.5/9 so halfway between 0 and 1/2 is 2.25/9 1 is less than 2,25 so Zero
x = sqrt (215) = 14.663 which is about 14.65
I assume that you mean H(x)= (x+4) / (3x-5) x = (y+4)/ (3y-5) (3y-5) x = y+4 3 x y - 5 x = y + 4 y - 3 x y = 4 - 5 x y (1 - 3x) = (4-5x) y = (4-5x)/(1-3x) which is y = (5x-4)/(3x-1)
change in velocity / change in time = (0-4) / time = -4 / time 207 = average speed * time average speed = (4+0)/2 = 2 m/s so time = 207/2 =103.5 s so a = - 4/103.5 m/s^2 (not much friction :)
4/5 * 10/13 = (4*10) / (5*13) = (4*2)/13 = 8/13
It does not help the student much just to type the answer. Moreover I do not agree with it.
100 -32 = 68 so 0.68 m = 102 m = 102 / 0.68
Take a cut at it yourself. I already answered one. Which do you think?
(3.8 - 3) / 10 look at the question below this one.
I mean -x * -y = +xy
- x * - x = +x
You are welcome.
B is NOT true D is NOT true
a = change in speed / change in time = (4 - 2) /(20-10) = 2/10 = 0.2 m/s^2
1/4 in = 1 ft = 12 in scale factors .25 in / ft and .25 in / 12 in which as you said is 1/48 so 1 in * (1 ft/.25 in) = 4 ft 1 in * (12 in / .25 in) = 48 in
x = 8 y = 5 tan angle above x (east) axis = 5/8 so angle above east axis = 32 degrees north of east so 90 - 32 = 58 degrees compass bearing East of North
use meters and kilograms or I get confused original momentum = 0.5 * 0.2 - 0.1 * 0.1= 0.09 kg m/s final momentum = 0.6*v final momentum = original so 0.6 v = 0.09 v = 0.15 m/s original ke = (1/2)[0.5*(0.2)^2 + 0.1(0.1)^2] = .5[.02+.001] = 0.0105 Joules
momentum before = .5 * .5 + .5 * 0 = .25 energy before = (1/2) (.5) .5^2 = (1/2) .5^3/2 momentum after = .5 * v1 + .5 V2 = .25 still energy after = (1/2) .5 v1^2+(1/2)(.5) v2^2=(1/2)(.5)(v1^2+v2^2) =(1/2)(.5)^3/2 still so v1+v2 = .5 so v2=.5-v1 and v1^2+
Now just a second. I am not your desk calculator. But this is trivial. if he were stationary of the carrier it would be 15 m/s If he were running back at 15,it would be zero if he ran at 3 it would by 15 - 3
the real question is how long to fall 5.4 meters the easy way is to say potential energy at top = kinetic energy at bottom to find speed at bottom (1/2) m Vb^2 = m g h Vb = sqrt(2 g h) = sqrt (2*9.81*5.4) = 10.3 m/s at bottom since v is linear with
It only has vertical speed. That speed is zero at the top. ======================= Now the real one at top vertical velocity is zero HOWEVER the is NO horizontal force, so horizontal component is constant for the whole trip u = 143 cos 12 = 140 m/s
Sketch them on a number line but 70 - 68 = +2 , 2 units away 60 - 68 = - 8 , 8 units away
Brute force, check my arithmetic y = a x^2 + b x + c first two points: -7 = 36 a - 6 b+ c -2 = 121 a -11 b + c ---------------------------------subtract -5 = -85 a + 5 b second and third points: -2 = 121 a - 11 b + c 1 = 64 a - 8 b + c
x²-3x+2 = (x-1) (x-2) so your function is f(x)=3x/(x-2) for x≠1,2,f(1)= -3,f(2)=4 yes f(1) = -3 , no problem with continuous there if f(1) given as -3 but at x = 2 the thing blows up as we approach x = 2 and saying that f(2)= 4 does not help.
Try and you will get help if stuck.
I am simply not going to just do that for you. draw a number line zero in the middle positive to the right negative to the left -51 will be far left + 51 will be far right zero at zero now finish and list starting at the far right
I just did that below
2300 g = 2.3 kg F = m * a 6.2 = 2.3 * a a = 2.7 m/s^2
(2/3)(6/7) = (2*6) / (3*7) = (2*2) / 7 = 4/7 good guess
is that 5.7882 KILOGRAMS ?????? if so 5788 grams if it is grams then 6
0.60 * 30 = 18 kg
(1/4)(2/3) (3/5) = 6 / 60 = 1/10 m^3
0.372 * 29.3 g = 10.9 grams of Pb 10.9 g ( 1 mL / 11.4 g) = ( 10.9 / 11.4 ) mL of lead
F = m a so a = F/m = (7.3 / 3.2) m/s^2 note -- a Newton is 1 kg * 1 m/s^2
No the excess is left over and does not participate. 27.1 g * 1 mol/35.5g = 0.763 mol Cl for every mol Cl we use 1/3 mol Fe so we actually used 1/3 * 0.763 = 0.254 mol Fe 0.254 mol * 56 g/mol = 14.2 grams Fe (the rest is excess left over) so I get 27.1 +
whose jacket who's = who is
on a number line -3 is left of zero |-3| = |+3| = 3, which is 3 units to the right of zero
goes down 58 feet from 150 final altitude = 150 - 58
I am supposed to do all your homework for you?
Yes, absent any relativistic effects :)
a square pen is 7*7 = 49 square inches 1728 in^2 * (1 pens^2 / 49 in^2) = (1728/49) pens^2
You are welcome.
58 - 27 = 32 so yes 27 protons, 32 neutrons I am not going to do all these for you. I do not need the practiced but you do. Where is your work? Believe me the teachers here have complained about the new Jiska format. We are also frustrated.
d. 5/x-z typo I think ---- 5/(x-z)
1. First law ! 2. again 3. clue " unhindered " 4. That same old first law again. Conservation of momentum. 5. Which is not moving?
https://www.mathsisfun.com/definitions/polyhedron.html
If I put 131 people in 131 boxes, I have one person in each box. (Until one jumps out)
203 - 75 = 125+3 = 128 128 / 4 = 32
y = m x + b ? 5 y = -2 x + 6 now divide both sides by 5 y = -(2/5) x + 6/5 -2/5 is the slope and 6/5 is the y axis intercept
I could not find the one you said but this one seems pretty well explained: https://www.youtube.com/watch?reload=9&v=Xsth3AEF7gk
k x must be the same units as ω t which is 2 pi f t which is 2 pi t/T which is no units (angle) so k x must be no units so k must be 1/meter by the way if L is wavelength and T is period sin(kx-ωt) is the same as sin (2 pi x/L - 2 pi t/T) so kx has same
1.40 * 20 = 28
change in y = (127 - 95) = 32 change in x = 3-1 = 2 32/2 = 16
All you need force for is CHANGING the momentum, m V . First law, no force means CONSTANT momentum Second law, net force is rate of change of momentum. Third law, for every force exerted there is an equal and opposite reaction force.
Unfortunately you can not post a link here.
I suspect that the problem writer used 11 instead of 10 seconds for the second part, but that is wrong. Choose -75
first choose which two girls will race (no order yet) combinations of 10 girls 2 at a time = 10!/[ 2! (8!) ] = 45 same for the boys 45 ways for each choice of two girls I can chose a choice of two boys so if I choose group 1 of boys, I can choose any of
at t = 1 it is at x = 24 a = -6 so now start over for 10 seconds to get to t = 11 at new time = 0, Vi = +24 and a = -6 v = 24 - 6 t x = 24 + 24 t - (1/2)6 t^2 at t = 10 x = 24*10 - 3 (100) 240 - 300 is indeed not -99
You have the right idea about getting the speed at which it hits the floor. HOWEVER the velocity changes when it hits acceleration = change of velocity / change in time it is on the floor, so velocity goes from contact speed to zero in 0.04 seconds now
You try. I showed you how.
I already showed you how to do these problems. You try now. I took this course more than 70 years ago, do not need practice. Post your attempts.
We already discussed the fact that the vertical motion can be solved separately from the constant horizontal speed motion THERE IS NO DIFFERENCE between A and B vertical problem: a = -g = -9.81 m/s^2 v = Vi + a t = -9.81 t = -9.81*3 = - 39.4 m/s h = Hi +
http://jwilson.coe.uga.edu/EMT668/EMAT6680.2003.fall/Perry/Assign%204%20Triangle%20Proof/Triangle%20Proof.htm Look at circumcenter.
13/20 = 5*13 /5*20 = 65/100 = 0.65
bullet accelerates downward at about 9.8 meters/ second^2 If you throw a ball to someone do you not make allowance for it falling during flight?
DOWN vertical F = - m g where g is acceleration of gravity so a = -g v = Vi - g t h = Hi + Vi t - (1/2) g t^2 AND horizontal u = constant all during flight

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