Asked by Jim
                Find 3 consecutive positive integers whose product is 5 more than the cube of the middle number. 
Tried x*(x+1)*(x+2) = (x+1)^3 + 5, but that solves to x = -6 which isn't positive.
            
        Tried x*(x+1)*(x+2) = (x+1)^3 + 5, but that solves to x = -6 which isn't positive.
Answers
                    Answered by
            Steve
            
    4*5*6 = 120 = 5^3-5
-6 * -5 * -4 = -120 = -5^3 + 5
I suspect a typo in the problem.
    
-6 * -5 * -4 = -120 = -5^3 + 5
I suspect a typo in the problem.
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