Question
Find 3 consecutive positive integers whose product is 5 more than the cube of the middle number.
Tried x*(x+1)*(x+2) = (x+1)^3 + 5, but that solves to x = -6 which isn't positive.
Tried x*(x+1)*(x+2) = (x+1)^3 + 5, but that solves to x = -6 which isn't positive.
Answers
Steve
4*5*6 = 120 = 5^3-5
-6 * -5 * -4 = -120 = -5^3 + 5
I suspect a typo in the problem.
-6 * -5 * -4 = -120 = -5^3 + 5
I suspect a typo in the problem.