find three consecutive positive integers such that 4 times the first 13 more than the third.

2 answers

The two end digits cannot be even because subtracting one from the other would be an even difference. Explore the odd choices.

123, 345, 567, 789
n-1 , n , n+1

4(n-1)-13 = n+1

4 n - 4 - 13 = n+1

3 n = 18

n = 6

5, 6, 7