Asked by Casey
Find three consecutive odd positive integers such that 3 times the sum of all three is 152 less than the product of the first and second integers
Answers
Answered by
Reiny
let the 3 cosecutive odd numbers be
x-2 , x, and x+2
3(x-2 + x + x+2) = x(x-2) - 152
9x = x^2 - 2x - 152
x^2 - 11x - 152 = 0
(x-19)(x + 8) = 0
x = 19, or x = -8 , but x is to be positive
the 3 numbers are:
17, 19, and 21
check:
their sum = 57
3 times their sum = 171
product of first and second = 17(19) = 323
Is 171 less than 323 by 152 ? YES
All is good
x-2 , x, and x+2
3(x-2 + x + x+2) = x(x-2) - 152
9x = x^2 - 2x - 152
x^2 - 11x - 152 = 0
(x-19)(x + 8) = 0
x = 19, or x = -8 , but x is to be positive
the 3 numbers are:
17, 19, and 21
check:
their sum = 57
3 times their sum = 171
product of first and second = 17(19) = 323
Is 171 less than 323 by 152 ? YES
All is good
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