Asked by james
how to find two consecutive positive even integers such that the square of first increased by 2 is equal to 3 times the second.
Answers
Answered by
oobleck
If the even numbers are x and x+2, then you need
x^2 + 2 = 3x
Solve for x, and then discard the unwanted solution.
x^2 + 2 = 3x
Solve for x, and then discard the unwanted solution.
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