find three consecutive even integers such that the product of the second and the third exceed the product of the first and third by 20.
2 answers
P.S: The Checking part also needs to be correct...
let the middle number be x, then the first is x-2 and the third is x+2
x(x+2) - (x-2)(x+2) = 20
x^2 + 2x - (x^2 - 4) = 20
your turn to finish it
x(x+2) - (x-2)(x+2) = 20
x^2 + 2x - (x^2 - 4) = 20
your turn to finish it