Asked by sam
find three consecutive even integers such that the product of the second and the third exceed the product of the first and third by 20.
Answers
Answered by
sam
P.S: The Checking part also needs to be correct...
Answered by
mathhelper
let the middle number be x, then the first is x-2 and the third is x+2
x(x+2) - (x-2)(x+2) = 20
x^2 + 2x - (x^2 - 4) = 20
your turn to finish it
x(x+2) - (x-2)(x+2) = 20
x^2 + 2x - (x^2 - 4) = 20
your turn to finish it
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