Asked by sam

find three consecutive even integers such that the product of the second and the third exceed the product of the first and third by 20.
Answered by sam
P.S: The Checking part also needs to be correct...
Answered by mathhelper
let the middle number be x, then the first is x-2 and the third is x+2
x(x+2) - (x-2)(x+2) = 20
x^2 + 2x - (x^2 - 4) = 20

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