Asked by Alexis
find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer. [only an algebraic solution can give full credit]
Answers
Answered by
bobpursley
let n, n+2, n+4 be the three consectutive even integers.
(n+2)(n+4)-20=10n
multiply all that out, solve. It will be a quadratic.
(n+2)(n+4)-20=10n
multiply all that out, solve. It will be a quadratic.
Answered by
Alexis
thankx
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