Asked by Emily
                Find three consecutive positive even integers such that four times the first decreased by the second is 12 more than twice the third.
            
            
        Answers
                    Answered by
            Damon
            
    n-2, n,  n+2
4(n-2) - n = 12 + 2(n+2)
4 n - 8 - n - 12 - 2n - 4 = 0
n - 24 = 0
n = 24
22 , 24, 26
    
4(n-2) - n = 12 + 2(n+2)
4 n - 8 - n - 12 - 2n - 4 = 0
n - 24 = 0
n = 24
22 , 24, 26
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