Asked by Emily

Find three consecutive positive even integers such that four times the first decreased by the second is 12 more than twice the third.
Answered by Damon
n-2, n, n+2

4(n-2) - n = 12 + 2(n+2)

4 n - 8 - n - 12 - 2n - 4 = 0

n - 24 = 0

n = 24

22 , 24, 26
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