Asked by Jennifer
                find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7?
            
            
        Answers
                    Answered by
            Steve
            
    Let the numbers be x,x+2 and x+4.
x^2 + (x+2)^2 = (x+4)^2 - 7
x = 5
check:
25+49 = 81-7
yes
    
x^2 + (x+2)^2 = (x+4)^2 - 7
x = 5
check:
25+49 = 81-7
yes
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