Question
find two consecutive positive integers such that their product added to four times the smaller integer equals 36
Answers
let the two numbers be x and x+1
4x + x(x+1) = 36
x^2 + 5x - 36 = 0
(x+9)(x-4) = 0
x = 4 or x = -9, but x>0
x = 4
the two numbers are 4 and 5
4x + x(x+1) = 36
x^2 + 5x - 36 = 0
(x+9)(x-4) = 0
x = 4 or x = -9, but x>0
x = 4
the two numbers are 4 and 5
Related Questions
If three times the smaller of two consecutive integers is added to four times the larger, the result...
What is the smallest of 3 consecutive positive integers if the product of the smaller two integers i...
The product of two consecutive odd integers is 9 more than 10 times the smaller integer. Find the p...