Asked by rayleigh
find two consecutive positive integers such that their product added to four times the smaller integer equals 36
Answers
Answered by
Reiny
let the two numbers be x and x+1
4x + x(x+1) = 36
x^2 + 5x - 36 = 0
(x+9)(x-4) = 0
x = 4 or x = -9, but x>0
x = 4
the two numbers are 4 and 5
4x + x(x+1) = 36
x^2 + 5x - 36 = 0
(x+9)(x-4) = 0
x = 4 or x = -9, but x>0
x = 4
the two numbers are 4 and 5
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