jzee11

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Questions

The following questions were asked by visitors named jzee11.

Find out if the force is conservative or non-conservative if the work done is W = x^2.y - x.z^3 - z.

Draw a diagram to scale showing the direction in which a man must row across a river in order to reach a point directly opposite, if he rows 3 mile/hr while the speed of current is 2 mile/hr. My ans- with angle of 33' with straight line he wants to travel...

How mush force must be exerted at an angle of 45 to top of a table to push along a weight when the frictional resistance to be overcome is a force of 2kg. Force is given in kg so i understand like this: N=kg.m/s^2 so the force in N is such when applied to...

Answers

The following answers were posted by visitors named jzee11.

displacement = 5.58 cm

ball's velocity 25 m/s when it hits the ground. minimum velocity required is 8.85 m/s

Here what i did. a=0.0442 m/s^2 t1=30.8 s d=1 km =1000 m. find the initial velocity (speed)=Vo when car starts accelerating. From basic equation of acceleration, a = dv/dt = (V1-Vo)/(t1-t0) ; t0= 0s. Vo = V1 - a.t1 missing V1=d/t0 = 1000/30.8 = 32.46 m/s....

cross section must be in mm^2. So, l = 2.5m A = 1.0 mm^2 = 0.01 cm^2 = 10^-6 m^2 R = 0.75 ohm Then, resistivity (r) is r = (R.A)/l = (0.75.10^-6)/2.5 = 3x10^-7 ohm.m

(6) 11/36 (7) 1/216

Well, there are 11 possible combinations that one of two dices rolls 1. i.e. (1,1) (1,2),....(2,1), (3,1).... probability for single event P(1)= 1/36. then Adding all 11 events is P = P(1) + P(1) +P(1) +...... 11 times = 1/36 + 1/36 + 1/36 +..... =11/36....

electrical force (F) is proportional to electric field (E) and E is proportional to inverse square of the distance (1/r^2) between charges. Therefore, F ~ 1/r^2. Now compare the two force given F1 and F2 then F1/F2 = r2^2 / r1^2

Thanks Damon. but i need to show W=0 then force is conservative or W not=0 for non conservative force. My book says if Work done along a closed path is zero then force is conservative. That is W = line integration of (F.dr)=0 I don't know how to prove it.

rolling two dice together, what is the probability of getting (6,6)?

Thanks Damon. I converted x,y,z into spherical polar coordinates and proved it when theta =0 and 2pi. but your method is easy, all things cancel out and W=0 proved. Thanks

log (1/8)/log x =-3/2 ;now log is base 10. therefore, log (1/8) = -0.9030. then log x = -0.6020 find the anti-log and you have x = 0.25

simple math; if at (100+12)% the value is 896 then what is at 100%. percent value 112 896 100 x x = 100x896)/112

the 4% value is given then what is 100% value. 1823.94x100)/4 is the answer.

Here F2 > F1 so tension by F2 is F2 = -T but F1 is in the same direction as F2 F2 = -T + F1 T = -F2 + F1 T = -13.5i N

R=9.12m and @=25. Its initial velocity is by R=Vo^2.sin2@/g Vo=10.8 m/s Maximum height is achieved at mid point of distance covered, then tan@ = max height/(R/2) h=2.12 m

Put t=5 then (0.26, 20, 2.98)

let sqrt(x^2 + 1) = t differentiating w.r.t x then x.dx / sqrt(x^2 + 1) = dt substitution give int(t^2 - 1)dt = t^3/3 - t = [(x^2 + 1)^3/2 ]/ 3 - (x^2 +1)^1/2

d=displacement of spring F=applied force in the direction of displacement Work done by the Force is W=Fd

W=F.d F=(50-10) N W=40.10 W=400J

r0 =(6i + 3j) V0 =(4i + -1j) a =(4i + 0j) (a) velocity v1 at t=3 s v1 = v0 + at v1 = (4i + -1j) + (4i + 0j)3 v1 = (4i + -1j) + (12i + 0j) vi = (16i + -1j) (b) position r1 at t=3 s r1 = r0 + v0.t + (a.t^2)/2 r1 = (36i + 0j) (c) Magnitude |r1| =sqrt[(x1)^2...

there are 4 prime numbers between 1 to 10. 2,3,5,7 So, the probability = 4/10 = 0.4

use vf^2 = vo^2 + 2gs where vf = final velocity = 0 at max height. vo = initial velocity = 21 m/s. g = -9.8 m/s^2 s = max height. s = 22.5 m

work = Force times COS(angle) times displacement.

Bullet A hits the ground after 9 sec.

You can use L'Hospital rule several times as long as the form 0/0 or infinity/infinity is there. Using sinh(x) = 1/2(e^2 - e^-2); limit is 2sinh(x)-2x/x-sin(x) which is 0/0 form. applying L'Hospital rule; limit is 2(cosh(x)-1)/1-cos(x) which is 0/0 form....

tension=mass*acceleration=500N

during 0.405 sec there is no acceleration; therefore, V=d/t d=vt d=(15)(0.405) which is the distance car traveled before driver hits brake. Now, a=-6 m/s^2 and car's final velocity vf=0. initial velocity vo=15 m/s use vf^2 = vo^2 +2as to get s=distance tr...

velocity of marble before it hits the ground is v^2 = vo^2 + 2as vo=0, a=-g=-9.8 m/s^2, s=-1 m then v=sqrt[0 + (2)(-9.8)(-1)] momentum is P = mv =(50/1000)v kg.m/s

here vf =0 vo = 5m/s a=g.sin(theta) theta=20 degree g=-9.8 m/s^2 s=? use s= [vf^2 - vo^2]/2a Ans=1.4 m

cyclotron freq omega = (e/m).B = 2.pi.f then f f = (e/m).B/2.pi = 8.6 Hz = 8.6 cylce/sec