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A block is given an initial velocity of 5.80 m/s up a frictionless 19.5° incline. How far up the incline does the block slide b...Asked by Godwin
A block is given an initial velocity of 5.00 m/s up a frictionless 20degree incline. How far up the incline does the block slide before coming to rest?
Answers
Answered by
jzee11
here
vf =0
vo = 5m/s
a=g.sin(theta)
theta=20 degree
g=-9.8 m/s^2
s=?
use
s= [vf^2 - vo^2]/2a
Ans=1.4 m
vf =0
vo = 5m/s
a=g.sin(theta)
theta=20 degree
g=-9.8 m/s^2
s=?
use
s= [vf^2 - vo^2]/2a
Ans=1.4 m
Answered by
Carvogue
Hey there, I did the same question but I got 3.78m as my final answer. I used the same calculation and values that you did too.
Answered by
Anonymous
Yes my answer is also 3.73
Answered by
hOwl
The solution is correct but he/she used radians instead of degrees
Answered by
LUNAR
If you got 3.78, chances are you dropped the 2 in the denominator. 2a, not just a. 1.4 is correct.
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