a 50 g marble is released from a height 1 m above the floor. Calculate its momentum just before hitting the ground

Answer 1

velocity of marble before it hits the ground is

v^2 = vo^2 + 2as

vo=0,
a=-g=-9.8 m/s^2,
s=-1 m

then

v=sqrt[0 + (2)(-9.8)(-1)]

momentum is
P = mv
=(50/1000)v kg.m/s