Asked by kik
A 5-g marble, released form rest, was allowed to roll on a ramp whose lower end is 25 cm from the floor. When it left the ramp, it behaved like a body in projectile motion. What was the horizontal velocity of this marble when it left the ramp? With what momentum did it leave the ramp?
Answers
Answered by
bobpursley
You have to know something about the ramp to answer these questions.
Answered by
Anonymous
M= 1525g= 1.525 kg
W= 14.95 N
Force required to start the block into motion:
F= 0.685(9.8)= 6.71N
Force to maintain motion:
F= 0.512(9.8)= 5.02N
Compute µk and µs:
µk = 5.02/14.95 = 0.34 µs = 6.72/14.95 = 0.45
W= 14.95 N
Force required to start the block into motion:
F= 0.685(9.8)= 6.71N
Force to maintain motion:
F= 0.512(9.8)= 5.02N
Compute µk and µs:
µk = 5.02/14.95 = 0.34 µs = 6.72/14.95 = 0.45
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.