16 marbles
1. independent red * blue = 4/16 * 7/16
2. dependent red then blue = 4/16 * 7/15
3.in number two the probability of blue is impacted by the fact that you have taken a marble out. The two draws are not independent on problem 2
In a jar there are 4 red marbles 5 green marbles and 7 blue marbles.
1 what us the probability of selecting a red marble replacing it and then selecting a blue marble
2 What is the probability of selecting a red marble setting it aside and then selecting a blue marble
3 are the answers to part 1 and 2 the same why or why not
This is the only question i have on my school work if any one can plz help me that would be awesome
4 answers
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Shorty my link is being reviewed and I'll post the link.
Ok so
There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.
a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
Next, the probability of selecting a blue marble.
Multiply the probabilities together.
That is the probability for event a.
b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.
Multiply the probabilities together.
That is the probability for event b.
c.
Obviously:
So the answer is no.
There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.
a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
Next, the probability of selecting a blue marble.
Multiply the probabilities together.
That is the probability for event a.
b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.
Multiply the probabilities together.
That is the probability for event b.
c.
Obviously:
So the answer is no.
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