In a jar there are 4 red marbles 5 green marbles and 7 blue marbles.

1 what us the probability of selecting a red marble replacing it and then selecting a blue marble

2 What is the probability of selecting a red marble setting it aside and then selecting a blue marble
3 are the answers to part 1 and 2 the same why or why not
This is the only question i have on my school work if any one can plz help me that would be awesome

4 answers

16 marbles

1. independent red * blue = 4/16 * 7/16

2. dependent red then blue = 4/16 * 7/15

3.in number two the probability of blue is impacted by the fact that you have taken a marble out. The two draws are not independent on problem 2
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Ok so

There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.

a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.

Next, the probability of selecting a blue marble.

Multiply the probabilities together.

That is the probability for event a.

b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.

Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.

Multiply the probabilities together.

That is the probability for event b.

c.
Obviously:

So the answer is no.
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