Asked by Jeffery
In a bag there are 2 red marbles 3 white marbles and 5 blue marbles. Once a marbel is picked it is not replaced. Find the following probabilities:
P(red,then white)
P(blue, then red)
P(red, red, red)
P(blue, blue, white)
P(red,then white)
P(blue, then red)
P(red, red, red)
P(blue, blue, white)
Answers
Answered by
Steve
all are basically the same. The total number of marbles drops after each selection. For example,
P(blue, blue,white) = 5/10 * 4/9 * 3/8
P(blue, blue,white) = 5/10 * 4/9 * 3/8
Answered by
Jeffery
But how would you solve the other 3 then
Answered by
Steve
for each draw, it is the number of that color, divided by the total number of marbles. For more than one draw, just multiply the fractions.
Take a look at what I did. It should become clear.
Take a look at what I did. It should become clear.
Answered by
Anonymous
I still don't understand.
Answered by
Steve
Look. If there are 12 balls, and 5 are red, the chance of getting a red ball is 5/12.
After you have drawn that red ball, there are only 4 reds and 11 balls, so the chance of getting a 2nd red is 4/11
and so on.
After you have drawn that red ball, there are only 4 reds and 11 balls, so the chance of getting a 2nd red is 4/11
and so on.
Answered by
Paul
That makes 0 sense there’s 10 balls not 12 just say the answer
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