Question

Block A has a mass of 4.11 kg and block B has a mass of 5.1 kg. The blocks are connected by a string of negligible mass and are free to slide on a horizontal, frictionless surface. A force vectorA=(11.1 N)i is applied to block A and a force vectorB=(24.6 N)i is applied to block B. What is the tension in the string in Newtons?

Not sure how to solve tension in the horizontal position...

Answer 1

Here F2 > F1
so tension by F2 is
F2 = -T but
F1 is in the same direction as F2
F2 = -T + F1
T = -F2 + F1
T = -13.5i N