Asked by Terzungwe nicholas

Two identical charges repel each other with a force 0.1mN and are moved additional 5.0cm a part the repulsive force is reduced to 25 x 10^-6N, (a) How far were they originally (b) what is the size of the charges
Answered by Ms. Sue
Is physics your School Subject?
Answered by jzee11
electrical force (F) is proportional to electric field (E) and E is proportional to inverse square of the distance (1/r^2) between charges.

Therefore, F ~ 1/r^2.
Now compare the two force given F1 and F2 then

F1/F2 = r2^2 / r1^2

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