A long jump athlete take off at 25 degree with the horizo and achieves a jumping distance of 9.12 m.

Question

(i) calculate the initial take-off speed
(ii) calculate the maximum height of the jump.

Answer 1

R=9.12m and @=25.
Its initial velocity is by

R=Vo^2.sin2@/g
Vo=10.8 m/s

Maximum height is achieved at mid point of distance covered, then

tan@ = max height/(R/2)
h=2.12 m