the distance equals the flight time multiplied by the horizontal component of the takeoff speed
t = 2 {[s * sin(27.1º)] / g}
d = t * [s * cos(27.1º)]
7.73 = 2 * s^2 * sin(27.1º / 2) / g
An athlete performing a long jump leaves the ground at a 27.1 ∘ angle and lands 7.73 m away.
1). What was the takeoff speed?
Express your answer using three significant figures and include the appropriate units.
2).If this speed were increased by just 3.0%, how much longer would the jump be?
Express your answer using two significant figures and include the appropriate units.
1 answer
1 answer