why is COCl2 polar a.

  1. can you explain me how to do this question. any help would be much appreciated.1) If 0.025 mol of COCl2(g) is placed in a one
    1. answers icon 1 answer
    2. hrithik asked by hrithik
    3. views icon 558 views
  2. Phosgene is a potent chemical warfare agent that is now outlawed by international agreement. It decomposes by the reaction
    1. answers icon 1 answer
    2. Emem asked by Emem
    3. views icon 1,486 views
  3. The equation for synthesis of the poisonous gas COCl2 isCO(g) + Cl2(g)COCl2 If 43.2 kJ of energy is evolved when 39.5 g of COCl2
    1. answers icon 2 answers
    2. Melissa asked by Melissa
    3. views icon 2,477 views
  4. Carbonyl chloride, COCl2, is prepared by the reaction: CO(g) + Cl2(g) → COCl2(g)The suggested reaction mechanism is: Cl2(g)
    1. answers icon 5 answers
    2. views icon 94 views
  5. the initial pressure of phosgene gas (COCl2), was 1.31 atm. it was heated, and at equilibrium the pressure of CO was found to be
    1. answers icon 2 answers
    2. Blair asked by Blair
    3. views icon 701 views
  6. why is COCl2 polara. different electronegativities b. nonsymmetric c. tetrahedral d. symmetric e. trigonal planar more than one
    1. answers icon 1 answer
    2. lyne asked by lyne
    3. views icon 1,625 views
  7. Determine if it is polar or non-polar molecule:C3H6O C2H5OH SiCl4 NH3 CO2 C3H8 H2O N2 My ans are: Polar Polar Polar polar
    1. answers icon 1 answer
    2. nadira asked by nadira
    3. views icon 1,406 views
  8. 1.62 g of CoCl2 x (xH20) were heated. After heating only .88g of CoCl2 remained. What was the formula of the original hydrate?
    1. answers icon 3 answers
    2. Courtney asked by Courtney
    3. views icon 2,475 views
  9. Starting with o.3700 mol CO (g) and 5.400*10^-2 COCl2 (g), in a 3 liter flask at 668 K, how many moles of Cl2 will be present?CO
    1. answers icon 1 answer
    2. anonymous asked by anonymous
    3. views icon 500 views
  10. At 298K, Go = -67.4 kJ for the reactionCO + Cl2 --> CoCl2 Calculate the change in Gibbs free energy (in kJ) at the same
    1. answers icon 4 answers
    2. Mike asked by Mike
    3. views icon 767 views