Asked by Courtney
1.62 g of CoCl2 x (xH20) were heated. After heating only .88g of CoCl2 remained. What was the formula of the original hydrate?
Answers
Answered by
DrBob222
CoCl2 = 0.88 g
H2O = 1.62-0.88 = 0.74 g
Convert to moles.
moles CoCl2 = 0.88/molar mass
moles H2O = 0.74/molar mass.
Now find the ratio of moles H2O to one(1) mole CoCl2. The easy way to do that is to divide moles CoCl2 by itself, then divide the moles H2O by the same small number and round to a whole number.
H2O = 1.62-0.88 = 0.74 g
Convert to moles.
moles CoCl2 = 0.88/molar mass
moles H2O = 0.74/molar mass.
Now find the ratio of moles H2O to one(1) mole CoCl2. The easy way to do that is to divide moles CoCl2 by itself, then divide the moles H2O by the same small number and round to a whole number.
Answered by
mason
.46%
Answered by
chicken nuggets
chicken time
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.