Ask a New Question
Search
How do you solve: sin[arccos(-2/7)]
State the period and phase shift of the function y=-4tan(1/2x + 3pi/8)
a) 2pi, -3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, -3pi/8
4 answers
asked by
Lucy
1,506 views
Calculate the limit: lim(((arccos x)^(n+1))/((arccos x)^n) with x tends to 1-, for every n that belongs to N, and then prove
0 answers
asked by
Zisis
540 views
Evaluate
arctan(cot10Pi/9) sec(arccos(-1/6) csc(arcsec(5/3) sin(2 arccos(sqrt5/5)
1 answer
asked by
Liv
1,221 views
Rewrite the following expression as an algebraic function of x
sin(arccos(x/2)) I know sine is y, which is opposite over
1 answer
asked by
Em
617 views
How do you solve:
sin[arccos(-2/7)] ?
2 answers
asked by
anonymous
2,582 views
Please can you help me with this question?
Choose the option which is a false statement: A arctan(tan2/3pi))=-1/3pi B
1 answer
asked by
janet
644 views
(arcsin(x/2)+arccos(x/2))/arctan(x) = 3/2, solve for x if x >0. Thanks.
1 answer
asked by
Dan
696 views
Solve the equation for x.
arcsin(sq. rt.(2x)) = arccos(sq. rt(x))
0 answers
asked by
Erica
391 views
Write the trigonometric expression as an algebraic expression.
1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2X-ARCCOS X)
1 answer
asked by
AwesomeGuy
2,136 views
solve for x in the following equations:
1) sin(arcsin x) = 1 2) 2arcsin x = 1 3) cos(arccos x) = 1/3
3 answers
asked by
Abbey
614 views