How do you solve: sin[arccos(-2/7)]

  1. State the period and phase shift of the function y=-4tan(1/2x + 3pi/8)a) 2pi, -3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, -3pi/8
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    2. Lucy asked by Lucy
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  2. Calculate the limit: lim(((arccos x)^(n+1))/((arccos x)^n) with x tends to 1-, for every n that belongs to N, and then prove
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    2. Zisis asked by Zisis
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  3. Evaluatearctan(cot10Pi/9) sec(arccos(-1/6) csc(arcsec(5/3) sin(2 arccos(sqrt5/5)
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    2. Liv asked by Liv
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  4. Rewrite the following expression as an algebraic function of xsin(arccos(x/2)) I know sine is y, which is opposite over
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    2. Em asked by Em
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  5. How do you solve:sin[arccos(-2/7)] ?
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    2. anonymous asked by anonymous
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  6. Please can you help me with this question?Choose the option which is a false statement: A arctan(tan2/3pi))=-1/3pi B
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    2. janet asked by janet
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  7. (arcsin(x/2)+arccos(x/2))/arctan(x) = 3/2, solve for x if x >0. Thanks.
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    2. Dan asked by Dan
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  8. Solve the equation for x.arcsin(sq. rt.(2x)) = arccos(sq. rt(x))
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    2. Erica asked by Erica
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  9. Write the trigonometric expression as an algebraic expression.1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2X-ARCCOS X)
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    2. AwesomeGuy asked by AwesomeGuy
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  10. solve for x in the following equations:1) sin(arcsin x) = 1 2) 2arcsin x = 1 3) cos(arccos x) = 1/3
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    2. Abbey asked by Abbey
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