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AwesomeGuy
Questions (31)
Find the inverse of the following quadratic equation. Hint: Complete the square first.
y= 2x²+16x-5
3 answers
603 views
Find the inverse of the following quadratic equation. Hint: Complete the square first.
y= x²+14x+50
1 answer
738 views
Solve the equation for all values of x.
2sin(2x)-√3=0, on the interval [0,2π).
1 answer
516 views
Solve the equation for all values of x.
-2cos²x-sin x+1=0, on the interval [0,2π).
1 answer
599 views
Write the trigonometric expression as an algebraic expression.
1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2X-ARCCOS X)
1 answer
2,087 views
Verify the identities please.
1.) TAN(X+π)-TAN(π-X)= 2 TAN X 2.) SIN(X+Y)+SIN(X-Y)= 2 SIN X COS Y
2 answers
715 views
Directions: Use a graphing utility to approximate the solutions of the equation in the interval [0,2π) by setting the equation
0 answers
870 views
Verify the identities algebraically.
1.) TAN^5 X= TAN³X SEC²X-TAN³X 2.) COS³X SIN²X= (SIN²X-SIN^4X)COS X
1 answer
680 views
Verify the identity algebraically. This problem is very intriguing and awesome at the same time. It's wonderfully amazing!
1.)
1 answer
468 views
State the quadrant in which θ lies.
1.) CSC θ is greater than 0 and TAN θ is less than 0. 2.) SEC θ is greater than 0 and SIN
1 answer
2,421 views
Verify the identities.
1.) √1-COSθ/1+COSθ= 1+SINθ/SINθ 2.) SEC X SIN(π/2-X)= 1 3.) CSC X(CSC X-SIN X)+SIN X-COS X/SIN X +
1 answer
921 views
Verify the identity algebraically.
TAN X + COT Y/TAN X COT Y= TAN Y + COT X
1 answer
5,312 views
Verify the identities.
1.) SIN[(π/2)-X]/COS[(π/2)-X]=COT X 2.) SEC(-X)/CSC(-X)= -TAN X 3.) (1 + SIN Y)[1 + SIN(-Y)]= COS²Y 4.)
3 answers
859 views
Verify/Solve the identities.
1.) SIN^1/2 X COS X-SIN^5/2 X COS X 2.) Long problem, but it's fun to solve! SEC^6 X(SEC X TAN
0 answers
549 views
Solve the equation.
1.) COS X CSC X
1 answer
444 views
Google this:
5.1 using fundamental identities Comcast Click and open the first result that appears on your search (Result= PDF
1 answer
481 views
Let's solve this fun trigonometric fun math problem!
1.) SEC²X-1/SIN²X
1 answer
753 views
Solve the trigonometric equations.
1.) SIN²x(CSC²x-1) 2.) COT x SEC X 3.) COS²[(π/2)-x]/COS X (Note: These mathematical
1 answer
1,333 views
A ship is 50 miles east and 35 miles south of port. If the captain wants to sail directly to port, what bearing should be taken?
1 answer
3,288 views
Two fire towers are 30 km apart, tower A being due west of tower B. A fire is spotted from the towers, and the bearings from A
2 answers
1,467 views
An observer in a lighthouse 350 feet above sea level observes two ships directly offshore. The angles of depression to the ships
4 answers
4,990 views
A plane is 160 miles north and 85 miles east of an airport. If the pilot wants to fly directly to the airport, what bearing
1 answer
4,019 views
Surveying
A surveyor wishes to find the distance across a swamp. The bearing from A to B (Segment AB is opposite side of
2 answers
7,758 views
Wave Motion
A buoy oscillates in simple harmonic motion as waves go past. At a given time it is noted that the buoy moves a total
1 answer
1,081 views
Mountain Descent
A road sign at the top of a mountain indicates that for the next 4 miles the grade is 12%. Find the angle of the
1 answer
779 views
Height of a Kite
A 100-foot line is attached to a kite. When the kite has pulled the line taut, the angle of elevation to the
3 answers
2,247 views
Angle of Depression
Find the angle of depression from the top of the lighthouse 250 feet above water level to the water line of a
4 answers
2,047 views
Navigation
A ship leaves port at noon and has a bearing of S 29° W. If the ship sails at 20 knots, how many nautical miles south
1 answer
1,378 views
Height of a mountain
While traveling across flat land, you notice a mountain directly in front of you. The angle of elevation to
1 answer
1,430 views
A passenger in an airplane flying at an altitude of 10 kilometers sees two towns directly to the left of the plane. The angles
2 answers
4,680 views
The length of a shadow of a tree is 130 feet when the angle of elevation of the sun is θ°.
a) Write the height h of the tree as
1 answer
2,465 views
Answers (7)
1.) Apply the following method you used in #2! You should notably understand this already! Goodness grief! 2.) let A = arctan x let B = arccos x then we are looking for sin(A + B) . now, tan A = x , sin A = x/√(x^2+1) cos A = 1/√(x^2+1) ... create a
AWESOME! SUPERB! I had it right when you provided support. THANKS!
2.) SEC X COS X= 1 1/COS X*COS X/1= 1 BINGO! 3.) CSC²X-CSC X SIN X+SIN X/SINX-TAN X+ COS X/SIN X 1/SIN²X-1/SIN X*SIN X/1-TAN X+COS X/ SIN X 1/SIN²X-1-SIN X/COS X+COS X/SIN X 1/SIN²X-1-TAN X*1/TAN X= CSC²X COOL! Need help on #6 and 7 please. Thank you!
1.) 1/TAN[(π/2)-X]=COT X BINGO! SOLVED! 2.) SEC X/-CSC X 1/COS X ÷ -1/COS X 1/COS X * -SIN X/1 -TAN X YES BINGO! WOW!
Reiny thanks a lot for the help! I welcome you with a nice smile! Here is the website where I can show how the problems look/appear like... Google this: 4.8 applications and models Comcast Click the first result that appears on the web search page. Go to
Since I have also forgot to label the conversion for the solution, it is ultimately measured in FEET.
BP= 3091.79 AB/sin 2.5° = 3091.79/sin 4° 3091.785015 sin 2.5° = 134.8617682 134.8617682/sin 4° = 1933.33 Awesome! Thanks for the help!