Asked by AwesomeGuy
Verify the identity algebraically. This problem is very intriguing and awesome at the same time. It's wonderfully amazing!
1.) TAN³α-1/TAN α-1= TAN²α + TAN α + 1
1.) TAN³α-1/TAN α-1= TAN²α + TAN α + 1
Answers
Answered by
Reiny
For ease of typing, let tan a = x
so your question becomes,
prove
(x^3 - 1)/(x-1) = x^2 + x + 1
The numerator of the LS is a difference of cubes
LS = ( (x-1)(x^2 + x +1) )/(x-1)
= x^2 + x + 1
= LS
all done!
so your question becomes,
prove
(x^3 - 1)/(x-1) = x^2 + x + 1
The numerator of the LS is a difference of cubes
LS = ( (x-1)(x^2 + x +1) )/(x-1)
= x^2 + x + 1
= LS
all done!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.