Asked by Ciaria
Verify the identity .
cot (treta-pi/2) = -tan treta
cot (treta-pi/2) = -tan treta
Answers
Answered by
Steve
first off, it's <u>theta</u>, not <u>treta</u>!
cot(θ-π/2) = (1+cot(θ)cot(π/2))/(cot(π/2)-cot(θ))
= -1/cotθ
= tanθ
cot(θ-π/2) = (1+cot(θ)cot(π/2))/(cot(π/2)-cot(θ))
= -1/cotθ
= tanθ
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